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2 years ago

5

I'm desperate for help. Please help

2 answers:

Rus_ich [418]2 years ago

7 0

Remember that in PEMDAS, you do the parentheses first.

1. For each answer choice, do whatever is in the parentheses first.

2. Multiply that number to the one outside the parentheses

Hint: For this problem, If all the signs in the answer choice are multiplication, they will equal the same number.

alukav5142 [94]2 years ago

5 0

It would be a!

step by step : in PEMDAS you would completer the parentheses first. 10*7 =70 * 4 =280. 10*4=40 *7 also = 280 hope that helps!!

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What is the solutions of the equation 2 (x+2) ^2-4=28

JulsSmile [24]

Answer:

x = 2 x = -6

Step-by-step explanation:

2 (x+2) ^2-4=28

Add 4 to each side

2 (x+2) ^2-4+4=28+4

2 (x+2) ^2= 32

Divide by 2

2/2 (x+2) ^2=32/2

(x+2)^2 = 16

Take the square root of each side

sqrt((x+2)^2) =±sqrt( 16)

x+2 = ±4

Subtract 2 from each side

x+2-2 = -2±4

x = -2±4

x = -2+4 and x = -2-4

x = 2 x = -6

3 0

2 years ago

Can you please answer these 3 questions im having a hard time rn and i just need to relax but i really need to get this done, pl

Yanka [14]

Answer:

1. Infinitiely many solutions, one solution, no solutions

2.

y=-3/2x-4

y= x+1

3.

y=1/4x-2

y=1/4x+3

Step-by-step explanation:

4 0

2 years ago

Determine the point on the graph of the linear equation 2x + 5y = 19, whose ordinate is 1 1/2 times its abscissa.

rosijanka [135]

Answer:

(2, 3)

Step-by-step explanation:

2x + 5y = 19

5y = -2x + 19

y = $-\frac{2}{5} x + \frac{19}{5}$

P(abscissa, ordinate)

P(x, 1.5x)

P(2, 3)

$3 = -\frac{2}{5} (2) + \frac{19}{5}$

$3 = -\frac{4}{5} + \frac{19}{5}$

3 = 15/5

3 = 3

8 0

2 years ago

(-2,y) and (2,4); slope: 1/4

Oduvanchick [21]

Answer:

y =3

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8 0

1 year ago

If a spring is oscillating (moving) according to the velocity equation v(t) = 2sin(t) (in ft/s), then what is its displacement o

Feliz [49]

ANSWER

4 ft

EXPLANATION

The velocity equation of the oscillating spring is given by the function.

$v(t)=2 \sin(t) \: \: {ms}^{ - 1}$

To find the displacement function, we need to to Integrate the velocity function.

$s(t) = \int \: 2 \sin(t) dt$

$s(t) = - 2 \cos(t) + k$

At time t=0, there was no displacement.

This implies that,

$s(0) = 0$

$0= - 2 \cos(0) + k$

$0= - 2 + k$

$k = 2$

The displacement function then becomes,

$s(t) = - 2 \cos(t) + 2$

To find the displacement over the first π seconds, we put

$t = \pi$

into the equation for the displacement to get,

$s(\pi) = - 2 \cos(\pi) + 2$

$s(\pi) = - 2 ( - 1) + 2$

$s(\pi) = 2 + 2 =4 ft$

7 0

2 years ago