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3 years ago

5

I'm desperate for help. Please help

2 answers:

Rus_ich [418]3 years ago

7 0

Remember that in PEMDAS, you do the parentheses first.

1. For each answer choice, do whatever is in the parentheses first.

2. Multiply that number to the one outside the parentheses

Hint: For this problem, If all the signs in the answer choice are multiplication, they will equal the same number.

alukav5142 [94]3 years ago

5 0

It would be a!

step by step : in PEMDAS you would completer the parentheses first. 10*7 =70 * 4 =280. 10*4=40 *7 also = 280 hope that helps!!

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I'll use arithmetic series to find it.

First two-digit number divisible by 3 is 12, last such number is 99. Every 3rd number is divisible by 3.

So,

$a_1=12\\a_n=99\\d=3\\n=?\\\\a_n=a_1+(n-1)\cdot d\\99=12+(n-1)\cdot 3\\3n-3=87\\3n=90\\n=30$

<u>There are 30 such numbers.</u>

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Brilliant_brown [7]

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