Answer:
66.42° between height and hypotenuse
23.58° between base and hypotenuse
Step-by-step explanation:
Using the concept of cosine and sine, we know that cosine of an angle is equal to the adjacent divided by hypotenuse.
Similarly, sine of an angle is given by opposite divided by hypotenuse
Tangent is given by opposite divided by adjacent
In rhis case, we use cosine

Therefore, the angle between the hypotenuse and height is 66.42°
To find the angle between base and hypotenuse, since it is a right angle triangle then the other angle will be 90-66.42=23.58°
I can’t really see it get a clear picture
Multiply the coefficients and the powers of 10 with each other:

The numeric part simply yields

As for the powers of 10, you have to add the exponents, using the rule

So, we have

So, the final answer is

Answer:
The value of c = -0.5∈ (-1,0)
Step-by-step explanation:
<u>Step(i)</u>:-
Given function f(x) = 4x² +4x -3 on the interval [-1 ,0]
<u> Mean Value theorem</u>
Let 'f' be continuous on [a ,b] and differentiable on (a ,b). The there exists a Point 'c' in (a ,b) such that

<u>Step(ii):</u>-
Given f(x) = 4x² +4x -3 …(i)
Differentiating equation (i) with respective to 'x'
f¹(x) = 4(2x) +4(1) = 8x+4
<u>Step(iii)</u>:-
By using mean value theorem


8c+4 = -3-(-3)
8c+4 = 0
8c = -4

c ∈ (-1,0)
<u>Conclusion</u>:-
The value of c = -0.5∈ (-1,0)
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