1 year ago

Select the correct answer.

Mathematics

1 answer:

pishuonlain [190]1 year ago

4 0

Answer:

C. The equation has two valid solutions and no extraneous solutions.

Step-by-step explanation:

See attached file for complete work.

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3 years ago

Suppose that the functions p and q are defined as follows.p(x) = -2x + 1q(x)=-x?Find the following.

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First let us find

$(q\mathrm{}p)(x)$ $\begin{gathered} q(p(x))=q(-2x+1) \\ =-(-2x+1)^2 \\ So\text{ } \\ (q\mathrm{}p)(5)=-(-2\times5+1)^2 \\ =-(9)^2 \\ =-81 \end{gathered}$

Now let;s solve the second part

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11 months ago

Please find the square roots of the following complex number.

Nana76 [90]

Hey there,

First, find the square root of the given equation.

$\sqrt{z}=\sqrt{81(\text{cos}(\frac{4\pi}{9})+i\text{sin}(\frac{4\pi}{9})}\\=9\text{cos}\frac{1}{2}(2k\pi+(\frac{4\pi}{9}))+i\text{sin}\frac{1}{2} (2k\pi+(\frac{4\pi}{9}))$

Keep in mind that this is solved for k = 0 and 1.

Second, simplify.

$=9\text{cos}(\frac{2\pi}{9})+i\text{sin}(\frac{2\pi}{9})~\text{or}~9\text{cos}(\frac{11\pi}{9})+i\text{sin}(\frac{11\pi}{9})$

Best of Luck!

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