Answer:
Step-by-step explanation:
Find the slope of the line AB.
<u>The slope:</u>
- m = (11 - 9)/(11 - 7) = 2/4 = 1/2
Since the altitude is perpendicular to AB, it has a slope of -2.
The line with the slope of -2 and passes through point C(6, 16).
<u>Use point-slope equation to find the line:</u>
- y - 16 = -2(x - 6)
- y - 16 = -2x + 12
- y + 2x = 16 + 12
- 2x + y = 28
A = 2, B = 1, C = 28
The height at t seconds after launch is
s(t) = - 16t² + V₀t
where V₀ = initial launch velocity.
Part a:
When s = 192 ft, and V₀ = 112 ft/s, then
-16t² + 112t = 192
16t² - 112t + 192 = 0
t² - 7t + 12 = 0
(t - 3)(t - 4) = 0
t = 3 s, or t = 4 s
The projectile reaches a height of 192 ft at 3 s on the way up, and at 4 s on the way down.
Part b:
When the projectile reaches the ground, s = 0.
Therefore
-16t² + 112t = 0
-16t(t - 7) = 0
t = 0 or t = 7 s
When t=0, the projectile is launched.
When t = 7 s, the projectile returns to the ground.
Answer: 7 s
Answer:
$8.1
Step-by-step explanation:
Convert 45 yards of ribbon to feet through proper conversion factor.
(45 yards)(3 ft / 1 yard) = 135 feet
Divide this number by 5 to determine the number of 5-ft ribbon that customers can purchased.
n = 135 ft / 5 ft = 27
Then, multiply by $0.80.
R = (27)($0.80) = $21.6
The profit is equal to $21.6 and $13.50,
P = $21.6 - $13.50 = $8.1
Answer: $8.1
Answer:
The answer is not in the options, it is 67.5
Step-by-step explanation:
135/2 = 67.5