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3 years ago

5

Jonah tore the angles off a large paper triangle. Then he arranged the three paper angles with their points together so that the

re were no gaps and no overlaps. What kind of Angle did Jonah form?

1 answer:

bonufazy [111]3 years ago

7 0

Answer:

Jonah formed a straight angle.

Step-by-step explanation:

Acute angle is an angle less than 90 degrees.
Obtuse angle is an angle greater than 90 but less than 180 degrees.
Reflex angle is greater than 180
Straight angle is equal to 180.

We know 3 angles of a triangle (no matter scalene, isosceles, right, equilateral triangle) sum up to 180 degrees. So, if Jonah were to cut of the 3 angles and put them points together, no overlap, he would eventually have a 180 degree angle, or a straight angle.

Jonah formed a straight angle.

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Which function represents a reflection of f(x) = 2(0.35)x over the y-axis?

Zina [86]

The function that is a reflection of f(x) over the y-axis is h(x) = 2(0.35)^(-x)

<h3>How to determine the reflection?</h3>

The equation is given as:

f(x) = 2(0.35)^x

The reflection of a function over the y-axis is :

f'(x) = f(-x)

So, we have:

f(-x) = 2(0.35)^(-x)

From the list of options, we have

h(x) = 2(0.35)^(-x)

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2 years ago

The coordinates of ∆ABC are A(-3, 2), B(5, 8) & C(11, 0). Which type of triangle is ∆ABC? Select All that apply.

stepan [7]

Given:

The coordinates of ∆ABC are A(-3, 2), B(5, 8) & C(11, 0).

To find:

The type of the given triangle.

Solution:

Distance formula:

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using the distance formula, we get

$AB=\sqrt{(5-(-3))^2+(8-2)^2}$

$AB=\sqrt{(8)^2+(6)^2}$

$AB=\sqrt{64+36}$

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$AB=10$

Similarly,

$BC=\sqrt{(11-5)^2+(0-8)^2}$

$BC=\sqrt{(6)^2+(8)^2}$

$BC=\sqrt{36+64}$

$BC=\sqrt{100}$

$BC=10$

And,

$AC=\sqrt{(11-(-3))^2+(0-2)^2}$

$AC=\sqrt{(14)^2+(-2)^2}$

$AC=\sqrt{196+4}$

$AC=\sqrt{200}$

$AC=10\sqrt{2}$

Two sides of the triangle are equal, i.e., $AB=BC$ . So, the triangle is an isosceles triangle.

Sum of square of two smaller side is

$AB^2+BC^2=10^2+10^2$

$AB^2+BC^2=100+100$

$AB^2+BC^2=200$

$AB^2+BC^2=AC^2$

Using the Pythagoras theorem, we can say that the given triangle is a right triangle.

Therefore, the correct options are B and F.

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