Answer:
Everyone is raised differently, some people are used to handling certain situations better than others. For example, if someone is raised in an area with lots of sunlight and warm temperature and they decide to move to somewhere cloudy and cold when they grow up, the dramatic difference between temperatures could make this person 'crazy' and unable to adapt to simple situations in this climate, regardless of how easy it is to handle for others. This could be a metaphor for many situations.
The part of the phospholipid molecule that will face the water, as it is labelled to be hydrophilic would be the polar phosphate group. The correct response would be A.
Blood types:
AB +
AB -
A +
A -
B +
B -
O +
O -
It is possible to have a child with O blood despite the parents having different blood types.
While the man tested for B blood, he could have been a combination between type o and B whereas, the woman was a combination of type A and o. Since A/B are dominant, they would 'stand out' contrarily to o.
This means that their children could have AB or O blood.
Question is incomplete. Complete question is as follows:
You have decided to determine how many microbes are living on the lettuce in the salad bar at your favorite restaurant. You place 1 gram of lettuce and 99 mls of water in a blender and blend the mixture. This is sample A. You then transfer 1 ml of this dilution into to another that contains 9 mls of water. This becomes sample B. You next transfer 1 ml of sample B into a separate container that contains 9 mls of water. This is sample C. Next you transfer 1 ml each from samples B & C onto separate nutrient rich agar plates, swirl, let harden and incubate at 37C. When you examine the plates after 48 hours you find 110 colonies growing on plate C. How many microbes were living on that 1 gram of lettuce?
Answer:
1.1x10^6 microbes
Explanation:
When 1gm of lettuce is mixed with 99 ml of water, the microbe concentration is diluted 100 times (Sample A). 1 ml of sample A is mixed with 9ml of water to make sample B which further dilutes microbe concentration 10 times making the total dilution 1000 times. This process is repeated with sample B to make sample C increasing the dilution to 10000 times.
110 colonies are counted from this sample C. Each colony signifies a single microbe during plate counting method. So, 110 microbes were present on the plate. Original number of microbes = microbes counted * times of dilution =
110 * 10000 = 1100000 = 1.1x10^6 microbes
