Answer:
How far did the ship travel between the two observations of the lighthouse = 9.29
Step-by-step explanation:
the first step to answer this question is drawing the illustration as the attachment.
P is the ship, R is the light house and Q is the bearing.
PR is the distance between the ship and the light house, PR = 10.5
∠P = 42.8°, ∠Q = 59.7°
Thus, ∠R = 180° - ∠P - ∠Q
= 180° - 42.8°- 59.7°
= 77.5°
PQ is the the distance of the ship moving. We can use the sinus equation
= 
= 
PQ = (
)(sin 59.7°)
= 9.29
Answer:
Step-by-step explanation:
Given Equation:
Actually the given equation is the 2nd equation of motion
i.e. 
where 
because the astronaut jumps on the earth
and initial velocity 
to find time 
, put the given value of 
in the given equation, we get
it will take to reach the ground if he jumps on the Earth
Answer:
16 ft
Step-by-step explanation:
One of the other three sides is 12 ft. After that fence is subtracted from the total, there are 32 ft of fence left for the other two sides of the rectangle. That allows those sides to be 32 ft/2 = 16 ft long.
The rectangle can be 12 ft by 16 ft. The longer dimension is 16 ft.
Answer:
A
Step-by-step explanation:
Divide 6.8ft by 4in then you get 1.7 and the multiply 15 an 14 by 1.7 then you get 25.5 and 23.8 then multiply 25.5 with 23.8 and get 606.9
I believe the best answer is C- the yellow rectangle was reflected over both axes
