Answer:
n(U) = n(AUB) + n(AUB)'
Step-by-step explanation:
The cardinality of the universal set will be to add the cardinalities of both the union of A and B i.e (A U B) and and the compliments of A and B i.e n(AUB)'
P(A) = 0.7
P(B) = 0.8
P(A∩B) ⇒ When both event happens
P(A∩B) = 0.7 x 0.8 = 0.56
Answer: 0.56
Answer:
discrete
Step-by-step explanation:
This graph is discrete. A discrete graph has separate values, which are represented by multiple unconnected points. In continuous graphs, the values are all connected to each other. If this graph was continuous, then we would see a line rather than separate dots. The graph can also not be neither continuous nor discreet because it passes the vertical line test, meaning that it is a function.
Hope this helps :)
Answer:
C(n, 2)a^(n-2)b^2
Step-by-step explanation:
Generally, the expansion is written in decreasing powers of "a", so the first few terms would have variable constellations that look like ...
a^n, a^(n-1)b, a^(n-2)b^2, ...
The coefficients would be (in order), C(n, k) for k increasing from 0, so the coefficient of the 3rd term would be C(n, 2).
Answer:
4a - 20b - 3c
Step-by-step explanation:
6a - 5b - 8c - 15b - 2a + 5c
= 4a - 20b - 3c
