What we know:
Football field is 100 yards in length
End zones are 10 yards each in length
Perimeter between pylons is 306 2/3 yards
What we need to find:
a. Perimeter and area of one end zone
b. Perimeter and area of without end zones
c. Perimeter and area of playing field with end zones
First we need to find the measurements of the field between pylons using the perimeter of 306 2/3 yards. We already know the length is 100 yards so we need to find width (w).
P=2l + 2w
306 2/3=2 (100) + 2w
306 2/3= 200 + 2w
300 2/3-200=200-200+2w
106 2/3=2w
106 2/3/2=2/2w
53 1/3=w
a. Perimeter=2 (10)+2 (53 1/3)=126 2/3 yards
Area=10×53 1/3=533 1/3 yd²
b. Perimeter=2 (100)+2 (53 1/3)=306 2/3 yards
Area=100×53 1/3=5333 1/3 yd²
c. Perimeter=2 (120) + 2 (53 1/3)=346 2/3 yards
Area=120×53 1/3=6400 yd²
Equation
-4x + 16 = -116
solve for x
-4x + 16 = -116
subtract 16 to both sides
-4x + 16 - 16 = -116 - 16
simplify
-4x = -132
divide -4 to both sides
-4x/-4 = -132/-4
simplify
x = 33
answer: the number is 33
Answer:
It would be 750
Step-by-step explanation: You have to divide it by 5 and then times it by 3.
Answer:
use acacolator
Step-by-step explanation:
hhhhahahahahahahaahah pp
Answer:
A. 1
B. -10
Step-by-step explanation:
