I'll try to understand this but I don't really get it because I'm in middle school
since the diameter of the base of the cylinder is 6 feet, then its radius is half that, or 3 feet.
![\bf \textit{volume of a cylinder}\\\\ V=\pi r^2 h~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=3\\ h=9 \end{cases}\implies V=\pi (3)^2(9)\implies V=81\pi](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvolume%20of%20a%20cylinder%7D%5C%5C%5C%5C%0AV%3D%5Cpi%20r%5E2%20h~~%0A%5Cbegin%7Bcases%7D%0Ar%3Dradius%5C%5C%0Ah%3Dheight%5C%5C%5B-0.5em%5D%0A%5Chrulefill%5C%5C%0Ar%3D3%5C%5C%0Ah%3D9%0A%5Cend%7Bcases%7D%5Cimplies%20V%3D%5Cpi%20%283%29%5E2%289%29%5Cimplies%20V%3D81%5Cpi)
Dear Sweet21574, the answer is D. Squre pyramid.
Answer is acute and scalene
This triangle is acute since all angles (51, 79, 70) are all less than 90 degrees. It is a scalene triangle as well since none of the sides (10, 12.1 , 11) are equal to each other.
Here are the other definitions to help you in the future
equilateral- All sides are the same. Right - Has one right angle. Obtuse - Has an angle more than 90 degrees. Isosceles - Only two sides are the same. One is different.
Answer:

<u>The correct answer is letter c.</u>
Step-by-step explanation:
The area equation of a triangle is given by:
(1)
Where:
b is the base
h is the height
Let's find first the angle MJK (α), using the tangent definition.



Now, if α = 37° then β (angle JLK) must be:


Now, we can find the distance ML using again the tangent definition:



The base of the triangle LKJ will be:

Therefore, using equation (1) the area of △LKJ will be:


The correct answer is c.
I hope it helps you!