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AVprozaik [17]
2 years ago
13

Find the equation that passes through points A and B

Mathematics
2 answers:
Irina18 [472]2 years ago
3 0

Answer:

Step-by-step explanation:

A(1,7); B(-3,-1); slope m =(-1-7)/-3-1) = -8/-4 = 2

Equation of a line AB is

((y-y1) = m(x-x1)

y - 7 = 2(x-1)

y - 7 = 2x-2

y = 2x + 5

vovikov84 [41]2 years ago
3 0

Answer:

<em>y = 2x +5</em>

Step-by-step explanation:

<u>Equation of a line</u>

The point-slope form of the equation of a line is:

y - k = m ( x - h )

Where m is the slope and (h,k) is a point through which the line passes.

Suppose we know the line passes through points A(x1,y1) and B(x2,y2). The slope can be calculated with the equation:

\displaystyle m=\frac{y_2-y_1}{x_2-x_1}

The image provides two points A(1,7) and B(-3,-1), thus the slope is:

\displaystyle m=\frac{-1-7}{-3-1}

\displaystyle m=\frac{-8}{-4}

m = 2

Now we apply the point-slope form taking the point (1,7):

y - 7 = 2 ( x - 1 )

Operating:

y - 7 = 2x - 2

Adding 7:

y = 2x +5

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