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Mademuasel [1]
3 years ago
9

What is the slope and y intercept of the line 4x-2y=7

Mathematics
2 answers:
aleksklad [387]3 years ago
7 0
First put it into y=mx+b
-2y=-4x+7
y=2+7/-2
yi=-3.5
m=2
Misha Larkins [42]3 years ago
6 0
The slope is 2
and the intercept is -7/2
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Find the volume of this cone.
Andrews [41]

Answer:

V = 180 ft^3

Step-by-step explanation:

The volume of a cone is found by

V = 1/3 pi r^2 h  where r is the radius and h is the height

The diameter is 12 so the radius is 1/2 the diameter or 1/2(12) = 6

The height is 5 and we are using 3 for pi

V = 1/3 (3) *6^2 *5

V = 180 ft^3

4 0
3 years ago
What is the value of s?3/8 (s 9 ) = −19?
denpristay [2]
S=<span>−<span>1.546727
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8 0
3 years ago
-3x^{2}-21x-54 what are the zeros? (Solutions)
Irina-Kira [14]
The only way to solve if it is equal to something
assuming that the teacher wanted you to make it equal to zero do
0=-3x^2-21x-54

remember if we can do
xy=0 then assume x and y=0

so factor

0=-3x^2-21x-54
undistribute the -3
0=-3(x^2+7x+18)
remember 0 times anything=0 so
x^2+7x+18 must equal zero
use quadratice formula which is

if you have
ax^2+bx+c=0 then
x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}

x^2+7x+18
a=1
b=7
c=18

x=\frac{-7+/- \sqrt{7^{2}-4(1)(18)} }{2(1)}
x=\frac{-7+/- \sqrt{49-72} }{2}
x=\frac{-7+/- \sqrt{-23} }{2}
i=√-1
x=\frac{-7+/- i\sqrt{23} }{2}



the zerose would be
x=\frac{-7+ i\sqrt{23} }{2} or \frac{-7- i\sqrt{23} }{2}




4 0
3 years ago
Which is the best definition of a trapezoid? A.a parallelogram that can have 2 equal sides B.a parallelogram with no equal sides
lina2011 [118]
D a quadrilateral with one pair of parallel sides
7 0
3 years ago
The area of a sector of an circle of a radius 5 cm, formed by an arc of length is 3.5cm. what is the answer
Natali5045456 [20]

Answer:

8.75cm²

Step-by-step explanation:

First we need to find the angle subtended by the arc

L = theta/360 * 2pir

3.5 = theta/360 * 2*3.14(5)

3.5 = theta/360 * 31.4

theta/360 = 3.5/31.4

theta/360 = 0.11146

theta = 0.11146 * 360

theta = 40.13 degrees

Area of the sector = theta/360 * pir^2

Area of the sector = 40.13/360 * 3.14*25

Area of the sector = 40.13/360 * 78.5

Area of the sector  = 8.75cm

Hence the area of the sector is 8.75cm²

5 0
3 years ago
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