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aksik [14]
1 year ago
8

Use the distance formula to find the distance between the points given.(3,4), (4,5)

Mathematics
1 answer:
algol [13]1 year ago
6 0

Solution:

To find the distance between two points, the formula is

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Where

\begin{gathered} (x_1,y_1)=(3,4) \\ (x_2,y_2)=(4,5) \end{gathered}

Substitute the values of the variables into the formula above

d=\sqrt{(4-3)^2+(5-4)^2}=\sqrt{1^2+1^2}=\sqrt{1+1}=\sqrt{2}\text{ units}

Hence, the answer is

\sqrt{2}\text{ units}

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Answer:

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3 0
2 years ago
Satellites KA-1212 and SAL-11 have spotted a UFO. Scientists want to determine its distance from KA-1212 so they can later deter
ch4aika [34]

Answer:

The distance of UFO from KA-1212 is 1229.7 km.

Step-by-step explanation:

We are given that,

Distance between the satellites = 900 km

Angle made by the satellite KA-1212 = 60°

Angle made by the satellite SAL-11 = 75°

So, from the figure below,

The third angle is given by = 180° - (60°+75°) = 180° - 135° = 45°

Then, using the law of sines, we have,

\dfrac{x}{\sin 75}=\dfrac{900}{\sin 45}\\\\x=\dfrac{900\times \sin 75}{\sin 45}\\\\x=\dfrac{900\times 0.966}{0.707}\\\\x=\dfrac{869.4}{0.707}\\\\x=1229.7

<h3>Thus, the distance of UFO from KA-1212 is 1229.7 km.</h3>

6 0
3 years ago
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What is the sum of the roots of the polynomial shown below? x^3+2x^2-11x-12
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The answer to your question is -2.
8 0
4 years ago
Sphere A and Sphere B , are similar. The volumes of A and B, are 17 and 136 cubic centimetres, respectively. The diameter of B ,
xxMikexx [17]

Answer:

3

Step-by-step explanation:

Given: Sphere A and Sphere B are similar.

The volumes of A and B are 17 cm^3and 136

The diameter of B is 6 cm.

To find: diameter of A

Solution:

Let R denotes radius of sphere A and r denotes radius of sphere B.

Radius of sphere A= R

Diameter of sphere B = 6 cm

So, radius of sphere B (r) = \frac{6}{2}=3\,\,cm

Volume of sphere is \frac{4}{3}\pi(radius)^3

Volume of sphere A = \frac{4}{3}\pi(R)^3

\frac{\frac{4}{3}\pi R^3}{\frac{4}{3}\pi r^3}=\frac{17}{136}=\frac{1}{8}\\\frac{R^3}{r^3}=\frac{1}{8}\\\frac{R}{r}=\frac{1}{2}\\r=2R

Put r = 3 cm

3=2R\\R=\frac{3}{2}=1.5\,\,cm

Diameter of sphere A = 2 × Diameter

= 2 × 1.5

=3 cm

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Which statement about z in quadrilateral ABCD is correct?
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We don't know because we can't see it
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