Longitud = L Ancho = A
2A + 2L = 54
L = 2A Sustituir este valor por L en la primera ecuación:
2A + 2(2A) = 54
2A + 4A = 54
6A = 54
A = 9
También porque L = 2A,
L = 2(9) = 18
<span>A probability distribution is formed from all possible outcomes of a random process (for a random variable X) and the probability associated with each outcome. Probability distributions may either be discrete (distinct/separate outcomes, such as number of children) or continuous (a continuum of outcomes, such as height). A probability density function is defined such that the likelihood of a value of X between a and b equals the integral (area under the curve) between a and b. This probability is always positive. Further, we know that the area under the curve from negative infinity to positive infinity is one.
The normal probability distribution, one of the fundamental continuous distributions of statistics, is actually a family of distributions (an infinite number of distributions with differing means (ÎĽ) and standard deviations (Ď). Because the normal distribution is a continuous distribution, we can not calculate exact probability for an outcome, but instead we calculate a probability for a range of outcomes (for example the probability that a random variable X is greater than 10).
The normal distribution is symmetric and centered on the mean (same as the median and mode). While the x-axis ranges from negative infinity to positive infinity, nearly all of the X values fall within +/- three standard deviations of the mean (99.7% of values), while ~68% are within +/-1 standard deviation and ~95% are within +/- two standard deviations. This is often called the three sigma rule or the 68-95-99.7 rule. The normal density function is shown below (this formula won’t be on the diagnostic!)</span>
Assuming the figure has identifiable bases and sides, the total surface area is the sum of the areas of those:
... B. Base area + lateral area
Answer:
a = √93
a ≈ 9.64
Step-by-step explanation:
We can use the Pythagorean theorem for this: a² + b² = c²
c is given as the hypotenuse, which is the pole with a length of 17 ft
c² is 17²
b is a leg with a height of 14 ft
b² = 14²
We need to find the base leg, a, distance from the wall to the base of the pole.
Solve:
a² + 14² = 17²
a² + 196 = 289
a² = 93
a = √93
-Chetan K
