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Pepsi [2]
3 years ago
13

Please I need help really badly

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
8 0

Answer:

with what

Step-by-step explanation:

I can't really see the question

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Which set of values for x makes the inequality 12−x<7 true
kozerog [31]

Answer:

\{x:x>5\}

Step-by-step explanation:

Given

12 - x < 7

Required

Values of x that make it true

First: solve the inequality.

12 - x < 7

Collect Like Terms

- x < 7-12

- x < -5

Multiply both sides by -1

-1 * - x < -5 * -1

x > 5 --- The inequality changes when multiplied by a negative value

So, the solution implies that the value of x is greater than 5 (i.e. 6, 7, 8..)

Hence, the set is:

\{x:x>5\}

7 0
3 years ago
Calculate the slope.<br> (-12,-5) and (0, -8)
zhenek [66]

Answer:

-1/4

Step-by-step explanation:

slope is always rise/run so

(-8)-(-5)=-3

-3/12=-1/4

the slope is -1/4

Enjoy^^

6 0
3 years ago
Which is the equation of a hyperbola with directrices at y = ±2 and foci at (0, 4) and (0, −4)?
Advocard [28]

Answer:

Step-by-step explanation:

First off, I'm assuming that when you said "directrices" you mean the oblique asymptotes, since hyperbolas do not have directrices they have oblique asymptotes.

If we plot the asymptotes and the foci, we see that where the asymptotes cross is at the origin. This means that the center of the hyperbola is (0, 0), which is important to know.

After we plot the foci, we see that they are one the y-axis, which is a vertical axis, which means that the hyperbola opens up and down instead of sideways. Knowing those 2 characteristics, we can determine that the equation we are trying to fill in has the standard form

\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1

We know h and k from the center, now we need to find a and b. Those values can be found from the asymptotes. The asymptotes have the standard form

y = ±\frac{a}{b}(x-h)+k

Filling in our asymptotes as they were given to us:

y = ±\frac{2}{1}(x-0)+0 where a is 2 and b is 1. Now we can write the formula for the hyperbola!:

\frac{(y-0)^2}{4}-\frac{(x-0)^2}{1}=1 which of course simplifies to

\frac{y^2}{4}-\frac{x^2}{1}=1

4 0
4 years ago
How to calculate the perpendicular distance from a line produced?? Thanks!!!
kykrilka [37]

Answer:d=a2+b2 ∣a(x0)+b(y0)+c∣. So given a line of the form a x + b y + c ax+by+c ax+by+c and a point ( x 0 , y 0 ) , (x_{0},y_{0}), (x0,y0), the perpendicular distance can be found by the above formula.

Step-by-step explanation:

if that is any help

4 0
3 years ago
The probability that Rahul succeeds at any given free-throw is 70%, percent. He was curious how many free-throws he can expect t
True [87]

Answer:

Step-by-step explanation:is 13/20=0.65

8 0
3 years ago
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