A rhombus is a parallelogram with four equal sides and two sets of equal angles.
If the m<1=160°, then the angle opposite (3) would also be 160°.
m<3=160°.
Becuase it is a parallelogram, the sum of the measurment of two angles that share a line would be 180 (supplementary).
m<2 and m<4 is 20°.
9514 1404 393
Answer:
- 75 adult tickets
- 125 child tickets
Step-by-step explanation:
Let 'a' represent the number of adult tickets sold. Then (200-a) is the number of child tickets sold, and the revenue is ...
8a +5(200 -a) = 1225
3a = 225 . . . . . . . . . . subtract 1000, simplify
a = 75 . . . . . . . . . . . . .divide by 3
200 -a = 125
75 adult ($8) and 125 child ($5) tickets were sold.
__
<em>Additional comment</em>
The question asked here is "how many tickets did Kay sell?" The second line of your problem statement tells you the answer: "Kay sold 200 tickets ...". We have assumed that you are interested in the breakdown of tickets sold, even though that is not the question that is asked here.
Answer:
1120
Step-by-step explanation:
To find the possible number of steak dinners, you would multiply the number of choices for each part of the dinner. You would used combinations instead of permutations since the order of the toppings chosen or side dishes chosen do not matter. There are 5 choose 1 choices for types of steak, which is just 5. There are 8 choose 3 choices for side dishes, which is 56. There are 4 choose 3 choices for toppings, which is 4. 5*56*4 is 1120, so there are 1120 possible steak dinners.
Answer:
101.25 weeks
Step-by-step explanation:
890-80=810
810/8=101.25
69, 62, 64, 67, 62, 64, 63, 65, 60, 64<br>
1. Find the mean, median, and mode
marta [7]
First order them from the smallest number 60
to the biggest number 69
Mean:582.4
Median:64
Mode:62 and 64
