Answer:
0.1131 = 11.31% probability that a randomly selected stock will close up $0.75 or more.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Normally distributed with a mean of $0.35 and a standard deviation of $0.33.
This means that
.
What is the probability that a randomly selected stock will close up $0.75 or more?
This is 1 subtracted by the p-value of Z when X = 0.75. So



has a p-value of 0.8869.
1 - 0.8869 = 0.1131
0.1131 = 11.31% probability that a randomly selected stock will close up $0.75 or more.
1. 157 ÷ 43 = 3 R 28
2. Mrs. Silverstein received $105, divide 91 by 13 which is 7, them multiply 15 by the quotient, 7, and you'll get 105.
Answer:3:7
Step-by-step explanation:
Answer:
Your class period goes out to eat at Red Lobster. The total bill is $63.50. Mrs. Melanie wants to leave a 15% tip.
How much is the total bill?
Step-by-step explanation: