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Misha Larkins [42]
3 years ago
11

Thomas has $30 to spend at the amusement park. Rides cost $2 each and admission at the gate is $6. What is the maximum number of

rides that Thomas can go on?
A.2r + 6 < 30

B.2r + 6 = 30

C.6r + 2 = 30

D. 6r + 2 > 30
Mathematics
2 answers:
Rudiy273 years ago
7 0

Answer:

B.2r+6=30

Explanation:

It costs $6 dollars just to get in. Subtract 6 from 30. 30-6=24

Divide 24 by 2. 24 divided by 2 equals 12.

Dahasolnce [82]3 years ago
3 0

Let the number of rides = r

Multiply the price per ride by number of rudest over 2r, you then add the admission to that to get 2R + 6

He has $30 so the total he can spend has to be less than or equal to $30

2r + 6 <= 30

The closest answer is A.

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<h2>The value of x = - \dfrac{10}{3}</h2>

Step-by-step explanation:

The given expressiona are:

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