Can someone solve this pls 2 1+ 3 1 - 1- 6

Mrs. Bowman designed the rug shown . If it costs 22$ per square footage to make, how much will Mrs. Bowman pay for the rug?

vazorg [7]

Just multiply 22 by the number it says.

7 0

3 years ago

Read 2 more answers

Explain and Show the equation of line perpendicular to y=-1x+2 going through the point (6, 3)

valentinak56 [21]

Answer:

y = x-3 is the equation

Step-by-step explanation:

If two lines are perpendicular, the product of their slopes is -1

The general equation form of a straight line is;

y = mx + b

Fro the equation;

y = -1x + 2

The slope is -1

So the equation of the perpendicular line is as follows;

-1 * m = -1

m = 1

so we can use the point-slope equation form

That would be:

y-y1 = m(x-x1)

y-3 = 1(x-6)

y-3 = x-6

y = x-6+3

y = x-3

3 0

3 years ago

Can someone please HELP ME

marysya [2.9K]

Answer:

M= (1.5, .05)

N=(4, 3.5)

Step-by-step explanation:

pls mark brainliest

5 0

3 years ago

465.89 divided by 12

Scorpion4ik [409]

Answer:

the answer is 38.81833333333333

8 0

3 years ago

Fine length of BC on the following photo.

MrMuchimi

Answer:

$BC=4\sqrt{5}\ units$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

In the right triangle ACD

Find the length side AC

Applying the Pythagorean Theorem

$AC^2=AD^2+DC^2$

substitute the given values

$AC^2=16^2+8^2$

$AC^2=320$

$AC=\sqrt{320}\ units$

simplify

$AC=8\sqrt{5}\ units$

step 2

In the right triangle ACD

Find the cosine of angle CAD

$cos(\angle CAD)=\frac{AD}{AC}$

substitute the given values

$cos(\angle CAD)=\frac{16}{8\sqrt{5}}$

$cos(\angle CAD)=\frac{2}{\sqrt{5}}$ ----> equation A

step 3

In the right triangle ABC

Find the cosine of angle BAC

$cos(\angle BAC)=\frac{AC}{AB}$

substitute the given values

$cos(\angle BAC)=\frac{8\sqrt{5}}{16+x}$ ----> equation B

step 4

Find the value of x

In this problem

$\angle CAD=\angle BAC$ ----> is the same angle

so

equate equation A and equation B

$\frac{8\sqrt{5}}{16+x}=\frac{2}{\sqrt{5}}$

solve for x

Multiply in cross

$(8\sqrt{5})(\sqrt{5})=(16+x)(2)\\\\40=32+2x\\\\2x=40-32\\\\2x=8\\\\x=4\ units$

$DB=4\ units$

step 5

Find the length of BC

In the right triangle BCD

Applying the Pythagorean Theorem

$BC^2=DC^2+DB^2$

substitute the given values

$BC^2=8^2+4^2$

$BC^2=80$

$BC=\sqrt{80}\ units$

simplify

$BC=4\sqrt{5}\ units$

7 0

3 years ago