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2 years ago

Which pair or pairs of polygons are congruent?

Mathematics

2 answers:

Gemiola [76]2 years ago

8 0

Answer:

E. 1234

Step-by-step explanation:

#plato babes

Neporo4naja [7]2 years ago

6 0

Pair 2 I’m pretty sure

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Sergio is working on a research project involving the ages of students at Brooklyn College. After interviewing 500 students, he

Zinaida [17]

Answer:

The probability of of a randomly chosen student being exactly 21 years old.

= 1.293

Step-by-step explanation:

Step(i):-

Given Population size n = 500

Mean of the Population = 20 years and 6 months

= $20 + \frac{6}{12} = 20 +0.5 = 20.5 years$

Standard deviation of the Population = 2 years

Let 'X' be the range of ages of the students on campus follows a normal distribution

Let x =21

$Z = \frac{x-mean}{S.D}$

$Z = \frac{x-mean}{S.D} = \frac{21-20.6}{2} =0.2$

The probability of a randomly chosen student being exactly 21 years old.

P( Z≤21) = 0.5 + A( 0.2)

= 0.5 +0.793

= 1.293

6 0

3 years ago

What’s this hdhshxbbsncjdkckskxbsh

7nadin3 [17]

Answer:

i dunno what that means but i think maybe your keyboard broke so the type of letters is random??

5 0

3 years ago

1.5r – 3r + 8r + 2.5r

Svetllana [295]

Answer:

Step-by-step explanation:

5 0

3 years ago

Solve the equation x-20.7=9.5 for x

kenny6666 [7]

The answer will come out to 30.2

8 0

2 years ago

Read 2 more answers

Pedro bought lb of red sand and lb of brown sand to refill his sand box. Both types of sand cost $4.60 a pound. How much did Ped

Doss [256]

If we know that Pedro bought 1 $\frac{1}{4}$ pounds of red sand, and 5 $\frac{1}{2}$ pounds of brown sand, and they both cost $4.60, then we just have to add the individual amounts of sand, since they cost the same.

$1 \frac{1}{4} + 5 \frac{1}{2} = 6 \frac{3}{4}$

So Pedro bought $6 \frac{3}{4}$ lbs of sand overall. Now, we just need to multiply the cost per pound by the total amount of sand he bought.

$6 \frac{3}{4} * 4.6 = 31.05$

Pedro spent $31.05 on sand, which is answer choice B.
Hope that helped =)

4 0

3 years ago

Read 2 more answers