4rt33 or 4 times the square root of 33
4 = the square root of sixteen, so the square root of 16 times the square root of 33 = the square root of 628
Answer:
137 votes
Step-by-step explanation:
considering an election with 681 votes and 5 candidates up for the election
dividing the votes among'st 5 candidates
= 681 / 5 = 136.2 hence the least number of first-place votes needed by a candidate using the plurality method would be = 137 votes
136.2 + 136.2 + 136.2 + 136.2 + 136.2 = 681 ( dividing the votes equally )
136 + 136 + 136 + 136+136 = 680
hence the remaining vote = 681 - 680 = 1
least first-place vote = 136 + 1 = 137 votes
Answer:
<h3><u>Option 1</u></h3>
Earn $50 every month.
- Let x = number of months the money is left in the account
- Let y = the amount in the account
- Initial amount = $1,000

This is a <u>linear function</u>.
<h3><u>Option 2</u></h3>
Earn 3% interest each month.
(Assuming the interest earned each month is <u>compounding interest</u>.)
- Let x = number of months the money is left in the account
- Let y = the amount in the account
- Initial amount = $1,000

This is an <u>exponential function</u>.
<h3><u>Table of values</u></h3>
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From the table of values, it appears that <u>Account Option 1</u> is the best choice, as the accumulative growth of this account is higher than the other account option.
However, there will be a point in time when Account Option 2 starts accruing more than Account Option 2 each month. To find this, graph the two functions and find the <u>point of intersection</u>.
From the attached graph, Account Option 1 accrues more until month 32. From month 33, Account Option 2 accrues more in the account.
<h3><u>Conclusion</u></h3>
If the money is going to be invested for less than 33 months then Account Option 1 is the better choice. However, if the money is going to be invested for 33 months or more, then Account Option 2 is the better choice.