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SCORPION-xisa [38]
3 years ago
15

Trisha knit a total of 8 centimeters of scarf over 4 nights. How many nights will Trisha have to spend knitting in order to knit

a total of 48 centimeters of scarf? Assume the relationship is directly proportional.
Mathematics
2 answers:
tia_tia [17]3 years ago
8 0

Answer: 24 nights in total

Step-by-step explanation: 48 divided by 8=6 and so six sets in total and to get the number of days you times 6x4 and you get 24 days in total. Also to check the answer 4 is half of 8 and 24 is half of 48

Gnom [1K]3 years ago
6 0

Answer: 6

Step-by-step explanation:

You would divide the number by the other number to get the awnser

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Evaluate the. Expression x+ 9, if x= 8. 1, 2, 17, 89
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Which of the following fractions is equivalent to (−13)÷(−6)? Select two that apply.
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Assignment The operation teeter is defined on the set T= { 2, 3, 5, 7 } by x teeter y=[x+y+xy) mod.8 a - Construct mod.8 table f
rosijanka [135]

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Case A) tau_net = -243.36 N m, case B)    tau_net = 783.36 N / m,      tau_net = -63.36 N m,  case C)  tau _net = - 963.36 N m,

Explanation:

For this exercise we use Newton's relation for rotation

        Σ τ  = I α

In this exercise the mass of the child is m = 28.8, assuming x = 1.5 m, the force applied by the man is F = 180N

we will assume that the counterclockwise turns are positive.

case a

        tau_net = m g x - F x2

         tau_nett = -28.8 9.8 1.5 + 180 1

        tau_net = -243.36 N m

in this case the man's force is downward and the system rotates clockwise

case b

2 force clockwise, the direction of

the force is up

         tau_nett = -28.8 9.8 1.5 - 180 2

         tau_net = 783.36 N / m

in case the force is applied upwards

3) counterclockwise

       tau_nett = -28.8 9.8 1.5 + 180 2

        tau_net = -63.36 N m

system rotates clockwise

case c

2 schedule

tau_nett = -28.8 9.8 1.5 - 180 3

tau _net = - 963.36 N m

3 counterclockwise

      tau_nett = -28.8 9.8 1.5 + 180 3

      tau_net = 116.64 Nm

the sitam rotated counterclockwise

<h3><u><em>Cr: moya1316</em></u></h3>
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