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Harlamova29_29 [7]
3 years ago
9

The product of a number and six is eigth

Mathematics
1 answer:
Dmitrij [34]3 years ago
8 0
Is there an article to this?
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find the sum of a 9-term geometric sequence when the first term is 4 and the last term is 1,024 and select the correct answer be
olasank [31]
Hello,

u_{1} =4\\
 u_{2} =4*q\\
 u_{3} =4*q^2\\
...\\

 u_{9} =4*q^8\\\\
==\textgreater\ 4*q^8=1024\\
==\textgreater\ q^8=256\\
==\textgreater\ q=2\mbox{( and there is a problem in the question) } \ or \ q=-2\\
if\ q=2 \ then\  \sum_{i=0}^{8}\ 4*(2)^i= 4*\dfrac{1-2^9}{1-2} =2044\\

if \ q=-2 \ then\ \sum_{i=0}^{8}\ 4*(-2)^i= 4*\dfrac{1-(-2)^9}{1+2} =684\\





Answer B (but see the problem)
7 0
3 years ago
Read 2 more answers
Gradient from 2 - 1/2y = 0​
kirill115 [55]

Given :

  1. 2 - 1/2y = 0

To find :-

  • The gradient form .

Solution :-

<u>The </u><u>gradient</u><u> form</u><u>/</u><u> </u><u>slope</u><u> intercept</u><u> form</u><u> </u>

  • y = mx + c ,

<u>On </u><u>converting</u><u> </u><u>,</u>

  • 2 - 1/2y = 0
  • 1/2y = 2
  • y = 2*2
  • y = 4
  • y = 0x + 4
4 0
2 years ago
Which expression is equivalent to the expression below?
Mama L [17]

Answer:

5r + 2p + 6

Step-by-step explanation:

= 4r + 9 + r + 2p - 3

= 4r + r + 2p + 9 - 3

= 5r + 2p + 6

4 0
3 years ago
Solve the right triangle.<br> Round your answers to the nearest tenth.<br><br> Help!
maks197457 [2]

answer: 1/2 bh

Step-by-step explanation

3 0
3 years ago
Monica has 2 gallons of milk to make milkshakes. Each milkshake contains 1 cup of milk. There are 128 ounces in 1 gallon and 8 o
OlgaM077 [116]

Answer: 32 cups of milk

Step-by-step explanation:

The first thing to do is to convert the gallons of milk to milkshakes so that you are able to convert easier to cups.

There are 128 ounces in 1 gallon and Monica has 2 gallons. The amount of milk Monica has in ounces is:

= 128 * 2

= 256 ounces

Each cup is capable of holding 8 ounces and there are 256 ounces available so the number of cups of milk is:

= 256 / 8

= 32 cups of milk

3 0
3 years ago
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