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2 years ago

What are the real zeros of x^3+4x^2-9x-39

Mathematics

1 answer:

Shalnov [3]2 years ago

8 0

Answer:

3.07

Step-by-step explanation:

The zeros of the function also called the roots are the x-intercepts where the function crosses the x-axis. The zeros are the x-values at these points. To find them, graph the function and look closely around the x-axis for intercepts.

See attached picture.

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Someone help me please

Masteriza [31]

Answer:

$(5,1)$

Step-by-step explanation:

Hi there!

Midpoint = $\displaystyle (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )$ where the two endpoints are $(x_1,y_1)$ and $(x_2,y_2)$

Plug in the given information:

Midpoint = (5,3), Endpoint = (5,5)

$(5,3)=\displaystyle (\frac{5+x_2}{2},\frac{5+y_2}{2} )$ where $(x_2,y_2)$ is the other endpoint

Solve for $x_2$ :

$\displaystyle \frac{5+x_2}{2} =5\\\\5+x_2 =10\\x_2 =5$

Solve for $y_2$ :

$\displaystyle\frac{5+y_2}{2}=3 \\\\{5+y_2}=6\\y_2=1$

Therefore, the other endpoint $(x_2,y_2)$ is $(5,1)$ .

I hope this helps!

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