X intercept: when Y = 0
Y intercept: when X = 0
Plug into equation
4x + 6(0) = 12
4x = 12, x = 3
Therefore x int = (3,0)
4(0) + 6y = 12
6y = 12, y = 2
Therefore y int = (0,2)
Plug those points then draw a line through them
Answer:
g(x), and the maximum is 5
Step-by-step explanation:
for given function f(x), the maximum can be seen from the shown graph i.e. 2
But for the function g(x), maximum needs to be calculated.
Given function :
g (x) = 3 cos 1/4 (x + x/3) + 2
let x=0 (as cosine is a periodic function and has maximum value of 1 at 0 angle)
g(x)= 3 cos1/4(0 + 0) +2
= 3cos0 +2
= 3(1) +2
= 3 +2
= 5 !
Answer:
14
Step-by-step explanation:
So, the anti derivative= x^2 -.8x +C. Ignore C.
Plug in 2= 4-(2)(.8)=2.4
Plug in .4= .16-(.4)(.8)=-.16
2.4-(-.16)= 2.56