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2 years ago

С E A B G 77° D plz help.me

Mathematics

1 answer:

Snowcat [4.5K]2 years ago

4 0

90°-77°=13°.

the answer is 13°

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Plssss help meeeee!!!!!!!!!!!!!!!!!!!

igomit [66]

Answer:

b = -30

Step-by-step explanation:

-b/5 - 27 = -21

~Add 27 to both sides

-1/5b = 6

~Multiply -5 to both sides

b = -30

Best of Luck!

8 0

2 years ago

How would you write 6 × 6 × 6 × 6 as an exponential expression?

stepan [7]

The answer is 6⁴.

Exponent is the number of times the factor is being multiplied. For example:
x * x = x²
x * x * x = x³
x * x * x * x = x⁴
....
So:
6 * 6 * 6 *6 = 6⁴

8 0

3 years ago

Write four numbers that round to 700,000 when rounded to the nearest hundred thousand

Tanya [424]

690000
650000
670000
680000

6 0

3 years ago

Read 2 more answers

1.Alan is x years old .Tom is 5 years older than Alan. Write an expression for the total of their ages.

N76 [4]

Answer:

1. 2x + 5

2. 35 students walked

3. 1:18

Step-by-step explanation:

5 0

2 years ago

Sinx = 1/2, cosy = sqrt2/2, and angle x and angle y are both in the first quadrant.

Leviafan [203]

Answer:

Option D. 3.73

Step-by-step explanation:

we know that

$tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}$

and

$sin^{2}(\alpha)+cos^{2}(\alpha)=1$

step 1

Find cos(X)

we have

$sin(x)=\frac{1}{2}$

we know that

$sin^{2}(x)+cos^{2}(x)=1$

substitute

$(\frac{1}{2})^{2}+cos^{2}(x)=1$

$cos^{2}(x)=1-\frac{1}{4}$

$cos^{2}(x)=\frac{3}{4}$

$cos(x)=\frac{\sqrt{3}}{2}$

step 2

Find tan(x)

$tan(x)=sin(x)/cos(x)$

substitute

$tan(x)=1/\sqrt{3}$

step 3

Find sin(y)

we have

$cos(y)=\frac{\sqrt{2}}{2}$

we know that

$sin^{2}(y)+cos^{2}(y)=1$

substitute

$sin^{2}(y)+(\frac{\sqrt{2}}{2})^{2}=1$

$sin^{2}(y)=1-\frac{2}{4}$

$sin^{2}(y)=\frac{2}{4}$

$sin(y)=\frac{\sqrt{2}}{2}$

step 4

Find tan(y)

$tan(y)=sin(y)/cos(y)$

substitute

$tan(y)=1$

step 5

Find tan(x+y)

$tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}$

substitute

$tan(x+y)=[1/\sqrt{3}+1}]/[{1-1/\sqrt{3}}]=3.73$

7 0

2 years ago

С E A B G 77° D plz help.me​

С E A B G 77° D plz help.me