Ask question

Ask question

All categories

tino4ka555 [31]

2 years ago

12

In a particular baseball park, the distance from home plate down the third baseline to the bottom of the left field wall is 306

feet. In left field, at the end of the baseline, the wall is perpendicular to the ground and is 32 feet tall. Determine the distance from home plate to the top of the left field wall along the third base line.

1 answer:

alukav5142 [94]2 years ago

8 0

Answer:

Pythagorean Theorem

S = (306^2 + 32^2)^1/2 = 307.7 ft

You might be interested in

The length of a shadow of a building is 28m. The distance from the top of the building to the shadow is 38m. Find the height of

AlexFokin [52]

It appears that the Pythagorean theorem can be applied to this problem
(distance to shadow)² = (height of building)² + (length of shadow)²
(38 m)² = (height of building)² + (28 m)²
660 m² = (height of building)²
Then the height of the building is
height of building = √660 m ≈ 25.7 m

7 0

2 years ago

How many numbers are there between 1 and 1000 that dont include the digit 9

labwork [276]

999 I think... let me know if that is correct:)

8 0

3 years ago

1/4 (8s + 16) help please

Tresset [83]

Answer:

2s + 4

Step-by-step explanation:

use the distributive property:

1/4 (8z + 16)

2s + 4

Done!

8 0

2 years ago

I need to know the improper fractions answers for:

zmey [24]

Answer:

Part 1) $x=\frac{15}{2}\ units$

Part 2) $z=\frac{15\sqrt{3}}{2}\ units$

Part 3) $y= \frac{15\sqrt{3}}{4}\ units$

Part 4) $b= \frac{45}{4}\ units$

Step-by-step explanation:

step 1

Find the value of x

In the large right triangle

$cos(60^o)=\frac{x}{15}$ ----> by CAH (adjacent side divided by the hypotenuse)

Remember that

$cos(60^o)=\frac{1}{2}$

substitute

$\frac{1}{2}=\frac{x}{15}$

solve for x

$x=\frac{15}{2}\ units$ ---> improper fraction

step 2

Find the value of z

In the large right triangle

Applying the Pythagorean Theorem

$15^2=x^2+z^2$

substitute the value of x

$15^2=(\frac{15}{2})^2+z^2$

solve for z

$z^2=15^2-(\frac{15}{2})^2$

$z^2=225-\frac{225}{4}$

$z^2=\frac{675}{4}$

$z=\frac{\sqrt{675}}{2}\ units$

simplify

$z=\frac{15\sqrt{3}}{2}\ units$

step 3

Find the value of y

In the right triangle of the right

$sin(30^o)=\frac{y}{z}$ ---> by SOH (opposite side divided by the hypotenuse)

substitute the given values of y and z

Remember that

$sin(30^o)=\frac{1}{2}$

so

$\frac{1}{2}=y:\frac{15\sqrt{3}}{2}$

solve for y

$\frac{1}{2}= \frac{2y}{15\sqrt{3}}$

$y= \frac{15\sqrt{3}}{4}\ units$

step 4

Find the value of b

In the right triangle of the right

$cos(30^o)=\frac{b}{z}$ ---> by CAH (adjacent side divided by the hypotenuse)

substitute the given values of y and z

Remember that

$cos(30^o)=\frac{\sqrt{3}}{2}$

so

$\frac{\sqrt{3}}{2}=b:\frac{15\sqrt{3}}{2}$

solve for y

$\frac{\sqrt{3}}{2}= \frac{2b}{15\sqrt{3}}$

$b= \frac{45}{4}\ units$

7 0

3 years ago

If six more than the product of a number and -2 is greater than 10, which of the following could be that number

laiz [17]

To get that number in the problem, you need to translate first the word problem into mathematical expression.

We will let x as the number.
six more than the product of a number and -2 is greater than 10 can be written as (-2x) + 6 > 10
We will now solve for x to get the number.
   (-2x) + 6 > 10
Add -6 to both sides of the equation
      -2x + 6 - 6 > 10 - 6
      -2x > 4
Divide both sides of the equation with -2
Take note that if we divide a negative number in inequality, the inequality symbol will be change from greater than to less or from less than to greater than.
   -2x / -2< 4 / -2
   x < -2

Therefore, the number that we are looking for is less than -2.

7 0

3 years ago