Please help i have to get this all done by tommorw

Jackie's mother's sister has a son. How would that son be related to Jackie? He is Jackie's

KATRIN_1 [288]

Answer:

he is jackies cousin

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Find the vertex of the parabola. Is the vertex a maximum or minimum? What is the equation for the axis of symmetry?

Phoenix [80]

Answer:

(2,45) ; x = 2

Step-by-step explanation:

The method for solving for the vertex of a parabola from standard form involves converting to vertex form by forming a squared term. First, we need to actually put this equation into standard form, which dictates that the x^2 must never have a number in front of it (including -1). This means factoring out a negative 5 from the whole left side:

-5 (x^2 - 4x - 5) = y.

The next step is to pull the -5 out of the parentheses,

-5 (x^2 - 4x) + 25 = y,

which means multiplying it by the term on the outside to result in a positive 25. From here, we form the squardo term from what is inside the parentheses. We do this by changing the form of the equation, similar to how one changes the form of a fraction (multiplying by a number over the same number so that you are effectively multiplying by one). Inside of the parentheses, we a going to add a number and on the outside of the parentheses, we are going to subtract that number multiplied by what is in front of the parentheses (effectively adding zero to the equation):

-5 (x^2 - 4x + __) +25 - (-5*__) = y.

Now, the number that goes in the blank is the coefficient of the x divided by two and then squared:

__= (-4/2)^2,

__= 4.

From there, we just plug in the __ , simplify, and factor:

-5 (x^2 - 4x + (4)) + 25 - (-5*(4)) = y,

-5 (x^2 - 4x + 4) + 25 - (-20) = y,

-5 (x^2 - 4x + 4) + 45 = y,

-5 (x - 2) (x - 2) + 45 = y,

-5 (x - 2)^2 + 45 = y.

Now the equation is in vertex form, and from it, we can determe the vertex. The general equation for vertex form is

m (x - $x_{1}$ ) + $y_{1}$ = y,

where ( $x_{1}$ , $y_{1}$ ) is the vertex. <em>*Notice that there is a negative sign built in to the equation, so when you pull out </em> $x_{1}$ <em>, make sure that you leave behind a negative sign.</em> In our case, we pull out a positive two, leaving behind the negative sign. <em>*If it were a ( x + 2 ), we would change it into ( x - (-2)) and pull out the -2, leaving behind a negative sign.*</em>

This gives us a vertex of (2,45).

Now, the second part of the question asks for the equation of the axis of symmetry. The general equation for the axis of symmetry is

x = $x_{1}$ ,

since the axis of symmetry is just a vertical line that goes through the vertex. Plugging in $x_{1}$ then gives us

x = 2,

our axis of symmetry.

6 0

3 years ago

The median of a probability distribution can be defined as the number m such that Upper P (Upper X less than or equals m )equals

Alexxandr [17]

Answer:

tex]M=\beta ln(2)[/tex]

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate).

Solution to the problem

For this case we can use the following Theorem:

"If X is a continuos random variable of the exponential distribution with parameter $\beta$ for some $\beta \in R >0$ "

Then the median of X is $\beta ln (2)$

Proof

Let M the median for the random variable X.

From the definition for the exponential distribution we know the denisty function of X is given by:

$f_X (x) = \frac{1}{\beta} e^{-\frac{x}{\beta}}$

Since we need the median we can put this equation:

$P(X$

If we evaluate the integral we got this:

$\frac{1}{\beta} \int_0^M e^{- \frac{x}{\beta}}dx =\frac{1}{\beta} [-\beta e^{-\frac{x}{\beta}}] \Big|_0^M$

And that's equal to:

$1/2 = 1 -e^{- \frac{M}{\beta}}$

And if we solve for M we got:

$1-e^{- \frac{M}{\beta}} = \frac{1}{2}$

$e^{- \frac{M}{\beta}}=\frac{1}{2}$

If we apply natural log on both sides we got:

$-\frac{M}{\beta}=ln(1/2)$

And then $M=\beta ln(2)$

5 0

3 years ago

in comparing the galilean transformations with the lorentz transformations, what multiplicative factor appears in the lorentz tr

raketka [301]

In Lorentz transformations we have velocity based factors that is not present in Galilean ones.

<h3>What is lorentz transformations?</h3>

The relationship between two distinct coordinate frames that are moving relative to one another at a constant speed is known as a Lorentz transformation. Dutch physicist Hendrik Lorentz is credited with coining the name of the transformation. There are two frames of reference: Inertial Frames, which refer to motion that has a constant speed.

<h3>What are Galilean transformations?</h3>

The relationship between two distinct coordinate frames that are moving relative to one another at a constant speed is known as a Lorentz transformation. Dutch scientist Hendrik Lorentz is credited with coining the term transformation. There are two frames of reference: Inertial Frames, which relate to motion that has a constant speed.

Any and all rulers and other self-contained length standards, such as those you might use to set up a measurement frame, can be contracted in length based on velocity. This results in the Lorentz factor at the place in the LT.

Any and all clocks and other physically independent systems, such as those used to record events in a measurement frame, are subject to velocity time dilation. As a result, the LF is temporarily in the LT.

The fact that applying Einstein synchronisation individually for each measurement frame turns out to be natural. Consequently, the position-dependent synchronisation offset between the clocks of one measurement frame and those of the other is represented by the enigmatic second term in the LT for the time.

To learn more about transformations click the following link :-

brainly.com/question/1548871

#SPJ4

7 0

1 year ago

I got 97.27 from 25% exam and on the project I got 97 and it is 25% and on the practical got 93.33 from 20%.

Sladkaya [172]

Contribution of the exam score to your ultimate grade: $0.25\cdot97.27\approx24.32$

Contribution of the project: $0.25\cdot97=24.25$

Contribution of the practical: $0.20\cdot93.33\approx18.67$

Contribution of the final exam: $0.30x=y$ , where $x$ is the score you get on the final exam and $y$ is the percentage that score contributes to your grade.

You want to end up with an A, a minimum grade of 90%, so

$24.32+24.25+18.67+y=90\implies y=22.76$

Then the minimum score you need to get on the exam is

$0.30x=22.76\implies x=\dfrac{22.76}{0.30}\approx75.87$

6 0

3 years ago