For the dilation with center (0,0) shown on the graph, your friend says the scale factor is 8/3

Evaluate the expreesion 41

irakobra [83]

Answer:

i'm pretty sure 41 is not an expression

Step-by-step explanation:

7 0

2 years ago

Subtract the following equation

Ksenya-84 [330]

Answer:

its just a black screeeeen

Step-by-step explanation:

8 0

3 years ago

The thickness of a part is to have an upper specification of 0.925 and a lower specification of 0.870 mm. the average of the pro

SVETLANKA909090 [29]

To solve this problem, we make use of the z statistic. The formula for the z score is:z score = (x – u) / swhere x is the sample value = 0.90, u is the sample mean = 0.917, and s is the standard deviation = 0.005
Therefore:z score = (0.90 – 0.917) / 0.005z score = -3.4
From the standard probability tables, the p-value for a right tailed test of z = -3.4 is:P = 0.9997
Therefore there is a 99.97% chance that it will be above 0.90 mm

7 0

3 years ago

A recipe requires 1\4 of a cup of cranberries for 1 batch. How many beaches of scones can be made using 6 1/2 cups of cranberrie

TiliK225 [7]

Answer:

26

Step-by-step explanation:

1 batch is 1/4 cups of cranberries.

This means that we have to find the number of groups of 1/4 in 6 1/2 cups to find the number of batches.

(The decimal forms of these numbers are 6.5 and 0.25)

6.5/0.25=26

There are 26 batches

8 0

2 years ago

Chemistry is an experimental science in which a consistent system of measurements is used. Scientists throughout the world use t

Elena L [17]

Answer:

(a) 142 km trip requires 15.16 Liters of Gasoline

(b) The money spent is 69.34 euros or $87.37.

(c) The average speed of sprinter is 34.45 km/h.

(d) 4 lb of candy contains 0.559 kg of dietary fat.

Step-by-step explanation:

(a)

Given that;

Mileage = 22 mi/gal

Converting it to km/L

Mileage = (22 mi/gal)(1 gal/3.78 L)(1 km/0.6214 mi)

Mileage = 9.36 km/L

Now, the gasoline required for 142 km trip:

Gasoline Required = (Length of trip)/(Mileage)

Gasoline Required = (142 km)/(9.36 km/L)

Gasoline Required = 15.16 L

(b)

Given that;

Mileage = 30 mi/gal

Converting it to km/L

Mileage = (30 mi/gal)(1 gal/3.78 L)(1 km/0.6214 mi)

Mileage = 12.77 km/L

Now, the gasoline required for 142 km trip:

Gasoline Required = (Length of trip)/(Mileage)

Gasoline Required = (115 km/day)(7 days/week)/(12.77 km/L)

Gasoline Required = 63 L/week

Now, we find the cost:

Weekly Cost = (Gasoline Required)(Unit Cost)

Weekly Cost = (63 L/week)(1.1 euros/L)

Weekly Cost = 69.34 euros/week = $87.37

since, 1 euro = $1.26

(c)

Average Speed = (Distance Travelled)/(Time Taken)

Average Speed = 200 m/20.9 s

Average Speed = (9.57 m/s)(3600 s/1 h)(1 km/ 1000 m)

Average Speed = 34.45 km/h

(d)

22.7 g piece contains = 7 g dietary fat

(22.7 g)(1 lb/453.592 g) piece contains = (7 g)(1 kg/1000 g) dietary fat

0.05 lb piece contains = 0.007 kg dietary fat

1 lb piece contains = (0.007/0.05) kg dietary fat

4 lb piece contains = 4(0.007/0.05) kg dietary fat

4 lb piece contains = 0.559 kg dietary fat

8 0

3 years ago

For the dilation with center​ (0,0) shown on the​ graph, your friend says the scale factor is 8/3

For the dilation with center (0,0) shown on the graph, your friend says the scale factor is 8/3