Answer:
Nitrogen is limiting reactant while hydrogen is in excess.
Explanation:
Given data:
Mass of N₂ = 25 g
Mass of H₂ = 25 g
Mass of ammonia formed = ?
Solution:
Chemical equation:
N₂ + 3H₂ → 2NH₃
Number of moles of Nitrogen:
Number of moles = mass/ molar mass
Number of moles = 25 g/ 28 g/mol
Number of moles = 0.89 mol
Number of moles of hydrogen:
Number of moles = mass/ molar mass
Number of moles = 25 g/ 2 g/mol
Number of moles = 12.5 mol
Now we will compare the moles of both reactant with ammonia.
H₂ ; NH₃
3 : 2
12.5 : 2/3×12.5 = 8.3
N₂ ; NH₃
1 : 2
0.89 : 2×0.89 = 1.78
The number of moles of ammonia produced by nitrogen are less thus nitrogen is limiting reactant while hydrogen is in excess.
Answer: 2-Benzyloxyethanol is produced reaction in the fig. below.
Explanation:
Oxygen 47 Hydrogen 63
Silicon 28 Oxygen 25.5
Aluminum 7.9 Carbon 9.5
Iron 4.5 Nitrogen 1.4
Calcium 3.5 Calcium 0.31
Sodium 2.5 Phosphorus 0.22
Potassium 2.5 Chlorine 0.03
Magnesium 2.2 Potassium 0.06
Titanium 0.46 Sulfur 0.05
Hydrogen 0.22 Sodium 0.03
Carbon 0.19 Magnesium 0.01
All others <0.1 All others <0.01 Living matter
Answer: Least Common Multiplier of a6m, 0.003 moles 0.01elamos
Steps 6m, 0.003 moles
Compute an expression comprised of Factors that appear either in a6m or 0.003 moles
= 0.018elamos
Explanation:
