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velikii [3]
3 years ago
9

What group would this element be in?

Chemistry
1 answer:
Lesechka [4]3 years ago
6 0
Non-metals. it is fluorine i believe and in the periodic table it is under the non-metal category
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The specific heat capacity of gold is 0.128 J/g C. How much would be needed to warm 250.0 grams of gold from 25.0 C to 100.0 C.
madam [21]

Answer:

3,200 joules

Explanation:

q = mcΔT = (250.0 g)(0.128 j/g°C)(100°C -25°C) = 3,200 joules

7 0
4 years ago
Collect 1 liter of water then add 0.39
saw5 [17]

Answer:

You fill up the 5 liter bottle. Then pour the contents from the 5 liter to the 3 liter till the 3 liter is full. Once the 3 liter bottle is full, what is left in the 5 liter bottle is 2 liters. Then you empty out the 3 liter until it matches the height of the 5 liter. Pour the remaining contents of the 3 liter bottle in the 5 liter bottle to get exactly 4 liters.

3 0
3 years ago
Write complete ionic and net ionic equations for the reaction between sulfuric acid (H2SO4) and calcium carbonate (CaCO3).
svetlana [45]

Answer:

Complete ionic equation:

2H²⁺(aq) + SO₄²⁻(aq) + CaCO₃(s)   →  H₂O(l) + CO₂(g) + Ca²⁺(aq) + SO₄²⁻(aq)

Net ionic equation:

2H²⁺(aq) + CaCO₃(s)   →  H₂O(l) + CO₂(g) + Ca²⁺(aq)

Explanation:

Chemical equation:

H₂SO₄(aq) + CaCO₃(s)   →  H₂O(l) + CO₂(g) + CaSO₄(aq)

Balanced chemical equation:

H₂SO₄(aq) + CaCO₃(s)   →  H₂O(l) + CO₂(g) + CaSO₄(aq)

Complete ionic equation:

2H²⁺(aq) + SO₄²⁻(aq) + CaCO₃(s)   →  H₂O(l) + CO₂(g) + Ca²⁺(aq) + SO₄²⁻(aq)

Net ionic equation:

2H²⁺(aq) + CaCO₃(s)   →  H₂O(l) + CO₂(g) + Ca²⁺(aq)

4 0
3 years ago
Read 2 more answers
What is the pH of a solution that has a [H+] of 1.5 × 10−5 M?
Alexandra [31]

pH = 4.82

[H⁺] = 1.5 × 10⁻⁵ mol·L⁻¹.

pH = -log[H⁺] = -log(1.5 × 10⁻⁵) = 4.82

8 0
3 years ago
What type of protection would effectively protect against alpha particles?
kirza4 [7]
Alpha particles can<span> only travel a few inches and beta particles around 10 feet. ... However, living tissue inside the body offers no </span>protection against<span> inhaled or ingested alpha ... Thick, dense shielding is necessary to </span>protect against<span> gamma rays. so your answer would difinetly be uranium

</span>
5 0
3 years ago
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