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wel
2 years ago
15

2Nal + Cl2 → 2NACI + I2

Chemistry
1 answer:
Sati [7]2 years ago
7 0

Answer:

Mass of iodine = 1954.26 g

Explanation:

Given data:

Mass of chlorine react = 546 g

Mass of iodine produced = ?

Solution:

Chemical equation:

2NaI + Cl₂  →  2NaCl + I₂

Number of moles of chlorine:

Number of moles = mass/molar mass

Number of moles = 546 g/71 g/mol

Number of moles = 7.7 mol

Now we will compare the moles of chlorine with iodine.

                     Cl₂          :          I₂

                      1             :          1

                      7.7         :          7.7

Mass of iodine:

Mass = number of moles × molar mass

Mass = 7.7 mol × 253.8 g/mol

Mass = 1954.26 g

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Explanation:

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8 0
2 years ago
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Nataliya [291]

The daughter isotope  : Radon-222 (Rn-222).

<h3>Further explanation</h3>

Given

Radium (Ra-226) undergoes an  alpha decay

Required

The daughter nuclide

Solution

Radioactivity is the process of unstable isotopes to stable isotopes by decay, by emitting certain particles,  

  • alpha α particles ₂He⁴
  • beta β ₋₁e⁰ particles
  • gamma particles ₀γ⁰
  • positron particles ₁e⁰
  • neutron ₀n¹

The decay reaction uses the principle: the sum of the atomic number and mass number before and after decay are the same

Radium (Ra-226) : ₈₈²²⁶Ra

Alpha particles : ₂⁴He

So Radon-226 emits alpha α particles ₂He⁴  , so the atomic number decreases by 2, mass number decreases by 4

The reaction :

₈₈²²⁶Ra ⇒ ₂⁴He + ₈₆²²²Rn

4 0
2 years ago
How many moles of helium are needed to fill a balloon to a volume of 5.3 L at 22 ℃ and 632 mmHg?
son4ous [18]

Answer:

0.18 moles

Explanation:

Applying,

PV = nRT................... Equation 1

Where P = pressure, V = volume, n = number of moles, R = molar gas constant, T = temperature.

make n the subject of the equation

n = PV/RT............... Equation 2

Given: V = 5.3 L, T = 22 °C = (22+272) K = 295 K, P = 632 mmHg = (0.00131579×632) = 0.8316 atm,  R = 0.083 L.atm/K.mol

Substitute these values into equation 2

n = (0.8316×5.3)/(0.083×295)

n = 0.18 moles

6 0
3 years ago
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6 0
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