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wel
2 years ago
15

2Nal + Cl2 → 2NACI + I2

Chemistry
1 answer:
Sati [7]2 years ago
7 0

Answer:

Mass of iodine = 1954.26 g

Explanation:

Given data:

Mass of chlorine react = 546 g

Mass of iodine produced = ?

Solution:

Chemical equation:

2NaI + Cl₂  →  2NaCl + I₂

Number of moles of chlorine:

Number of moles = mass/molar mass

Number of moles = 546 g/71 g/mol

Number of moles = 7.7 mol

Now we will compare the moles of chlorine with iodine.

                     Cl₂          :          I₂

                      1             :          1

                      7.7         :          7.7

Mass of iodine:

Mass = number of moles × molar mass

Mass = 7.7 mol × 253.8 g/mol

Mass = 1954.26 g

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Explanation:

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This equation is balanced, we do not have the change any coefficients.

Step 2: The netionic equation

The net ionic equation, for which spectator ions are omitted - remember that spectator ions are those ions located on both sides of the equation - will.

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After canceling those spectator ions in both side, look like this:

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3 years ago
How many molecules are in 189.5 grams of no2?
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2 years ago
Anybody good at chemistry?
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Answer:

Explanation:

1)

Given data:

Mass of lead = 25 g

Initial temperature = 40°C

Final temperature = 95°C

Cp = 0.0308 j/g.°C

Heat required = ?

Solution:

Specific heat capacity: Cp

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

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m = mass of given substance

c = specific heat capacity of substance

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Q = 42.35 j

2)

Given data:

Mass  = 3.1 g

Initial temperature = 20°C

Final temperature = 100°C

Cp = 0.385 j/g.°C

Heat required = ?

Solution:

Specific heat capacity: Cp

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = Final temperature = initial temperature

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3)

Given data:

Mass of Al = ?

Initial temperature = 60°C

Final temperature = 30°C

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Solution:

Specific heat capacity: Cp

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

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m = mass of given substance

c = specific heat capacity of substance

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ΔT = -30°C

120 j = m × 0.897 j/g.°C  × -30°C

120 j = m × -26.91  j/g

m = 120 j / -26.91  j/g

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negative sign show heat is released.

4)

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Mass of ice = 1.5 g

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Q = m.c. ΔT

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30.0 j = 0.753 j/°C  × ΔT

30.0 j /0.753 j/°C  = ΔT

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Answer:

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