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Zolol [24]
3 years ago
9

I need help with this proof!

Mathematics
1 answer:
mr Goodwill [35]3 years ago
3 0

Answer:

∠B ≅ ∠F ⇒ proved down

Step-by-step explanation:

<em>In the </em><em>two right triangles</em><em>, if the </em><em>hypotenuse and leg</em><em> of the </em><em>1st right Δ ≅</em><em> the </em><em>hypotenuse and leg</em><em> of the </em><em>2nd right Δ</em><em>, then the </em><em>two triangles are congruent</em>

Let us use this fact to solve the question

→ In Δs BCD and FED

∵ ∠C and ∠E are right angles

∴ Δs BCD and FED are right triangles ⇒ (1)

∵ D is the mid-point of CE

→ That means point D divides CE into 2 equal parts CD and ED

∴ CD = ED ⇒ (2) legs

∵ BD and DF are the opposite sides to the right angles

∴ BD and DF are the hypotenuses of the triangles

∵ BD ≅ FD ⇒ (3) hypotenuses

→ From (1), (2), (3), and the fact above

∴ Δ BCD ≅ ΔFED ⇒ by HL postulate of congruency

→ As a result of congruency

∴ BC ≅ FE

∴ ∠BDC ≅ ∠FDE

∴ ∠B ≅ ∠F ⇒ proved

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3 years ago
Shane and Abha earned a team badge that required their team to collect no less than 2000 cans for recycling. Abha collected 178
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3 years ago
Angle $eab$ is a right angle, and $be = 9$ units. what is the number of square units in the sum of the areas of the two squares
Alla [95]
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Also, AEFG is a square of size \sqrt{9^2-x^2}, thus, the area of square AEFG is given by

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8 0
3 years ago
Help me please!!!!!!!!
pogonyaev

Answer:

1) 4

2) 1.5

3) 8

4) 1

5) 5

6) 9

Step-by-step explanation:

<h3>1)</h3><h3> √16</h3>

= √(4x4)

= √(4)²

<h3>= 4</h3>

<h3>2)</h3><h3>√2.25</h3>

= √(9/4)

= √(3x3)/(2x2)

= √(3)²/(2)²

= 3/2

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<h3>3)</h3><h3>6² ÷ 9 x 2 </h3>

= 36 ÷ 9 x 2

= 36 x 1/9 x 2

= 36/9 x 2

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= 4 x 2

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<h3>4)</h3><h3>12-2 / 6+4</h3>

= 10/10

<h3>= 1</h3><h3 /><h3>5)</h3><h3>√(16+9)</h3>

= √(25)

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= √(5)²

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= 63 ÷ 9 + |2|

= 63/9 + |2|

= 21/3 + |2|

= 7 + |2|

<h3>= 9</h3>

3 0
4 years ago
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