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3 years ago

I need help with this proof!

Mathematics

1 answer:

mr Goodwill [35]3 years ago

3 0

Answer:

∠B ≅ ∠F ⇒ proved down

Step-by-step explanation:

In the two right triangles, if the hypotenuse and leg of the 1st right Δ ≅ the hypotenuse and leg of the 2nd right Δ, then the two triangles are congruent

Let us use this fact to solve the question

→ In Δs BCD and FED

∵ ∠C and ∠E are right angles

∴ Δs BCD and FED are right triangles ⇒ (1)

∵ D is the mid-point of CE

→ That means point D divides CE into 2 equal parts CD and ED

∴ CD = ED ⇒ (2) legs

∵ BD and DF are the opposite sides to the right angles

∴ BD and DF are the hypotenuses of the triangles

∵ BD ≅ FD ⇒ (3) hypotenuses

→ From (1), (2), (3), and the fact above

∴ Δ BCD ≅ ΔFED ⇒ by HL postulate of congruency

→ As a result of congruency

∴ BC ≅ FE

∴ ∠BDC ≅ ∠FDE

∴ ∠B ≅ ∠F ⇒ proved

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Answer:

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Answer:

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further more [ getting value of n ]

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divide all sides by 5:

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