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Helga [31]
2 years ago
6

This is hard please help it makes no sense

Mathematics
2 answers:
posledela2 years ago
8 0

We will find the length of DE using trigonometric ratios. And the trigonometric ratio we will use here is

\sf \tan( \theta)  =  \frac{opposite}{adjacent}

  • Opposite = 17 m
  • Adjacent = DE
  • θ = 51°

\tt \tan(51°)  =  \frac{17}{x}

\tt \tan(51°)  \times x = 17

\tt \: x =  \frac{17}{ \tan(51°) }

\tt \: x≈13.766

\boxed{ \sf \: x≈13.8 \: (when \: rounded \: off)}

<em>Thus, Option C is the correct choice!!~</em>

tigry1 [53]2 years ago
3 0

Answer:

lk12

Step-by-step explanation:

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seropon [69]

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First Option is correct.

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Step-by-step explanation:

Given:

The given factor is.

f(x)=x^{3}+x^{2}-14x-24

We need to find the factors of given factor.

Solution:

f(x)=x^{3}+x^{2}-14x-24

Substitute (-4x-10x) in the place of -14x

f(x)=x^{3}+x^{2}-4x-10x-24

Rearrange the equation:

f(x)=(x^{3}-4x)+(x^{2}-10x-24)

Now we factorised the above equation.

The factors of x^{2} -10x-24=(x+2)(x-12)

Now we substitute (x+2)(x-12) in the place of x^{2} -10x-24

And in the place of x^{3}-4x=x(x^{2}-4)

f(x)=x(x^{2}-4)+(x+2)(x-12)

Simplify x^{2} -4=x^{2} -(2)^{2} = (x+2)(x-2)

f(x)=x[(x+2)(x-2)]+(x+2)(x-12)

Common factor for above function (x+2)

f(x)=(x+2)[x(x-2)+(x-12)]

Simplify.

f(x)=(x+2)[x^{2}-2x+x-12]

f(x)=(x+2)(x^{2}-x-12)

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So the factors of the function.

f(x)=(x+2)(x-4)(x+3)

Therefore, the factors of the given function are (x+2)(x-4)(x+3)

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