Help plz MATH question for ASM
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Given:
The sum of three numbers is 12 .
The sum of twice the first number, 3 times the second number, and 4 times the third number is 37 .
The difference between 7 times the first number and the second number is 25.
To find:
The three number.
Solution:
Let the three numbers are x, y and z respectively.
According to the question,
...(i)
...(ii)
...(iii)
From (iii), we get
Put value in (i).
...(iv)
Put value in (ii).
...(v)
Now, Multiply equation (iv) by 4 and subtract the result from (v).
Put x=4 in (iv).
Put x=4 in .
Therefore, the three numbers are 4, 3 and 5 respectively.