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Marina CMI [18]
3 years ago
5

Can anyone please help me with this with an explanation

Mathematics
2 answers:
bekas [8.4K]3 years ago
3 0

Answer:

x=6

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

5x+4x−68=34−8x

5x+4x+ −68=34+ −8x

(5x+4x)+(−68)=−8x+34(Combine like terms)

9x+−68=−8x+34

9x−68=−8x+34

Step 2: Add 8x to both sides.

9x −68+ 8x= −8x +34 +8x

17x −68 =34

Step 3: Add 68 to both sides.

17x −68 +68= 34 +68

17x=102

Step 4: Divide both sides by 17.

17x /17=  102/17

                                X=6   > final answer hope i could help :)

EleoNora [17]3 years ago
3 0

Step-by-step explanation:

Let's step through this line by line, looking for a spot where the friend could have made a mistake.

5x+4x-68=34-8x\\5x+4x=102-8x\\5x+4x+8x=102\\17x=102\\x=6

So, where could the friend have made their mistake? The key here is the transition from step 1 to step 2. What if we had subtracted 68 instead of adding it?

5x+4x-68=34-8x\\5x+4x=-34-8x\\5x+4x+8x=-34\\17x=-34\\x=-2

There it is. The friend's problem was that they had accidentally <em>subtracted</em> 68 to both sides when they should have <em>added</em> it.

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Answers:

  • Part a)  \bf{\sqrt{x^2+(x^2-3)^2}
  • Part b)  3
  • Part c)   2.24
  • Part d)  1.58

============================================================

Work Shown:

Part (a)

The origin is the point (0,0) which we'll make the first point, so let (x1,y1) = (0,0)

The other point is of the form (x,y) where y = x^2-3. So the point can be stated as (x2,y2) = (x,y). We'll replace y with x^2-3

We apply the distance formula to say...

d = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\\\\d = \sqrt{(0-x)^2+(0-y)^2}\\\\d = \sqrt{(0-x)^2+(-y)^2}\\\\d = \sqrt{x^2 + y^2}\\\\d = \sqrt{x^2 + (x^2-3)^2}\\\\

We could expand things out and combine like terms, but that's just extra unneeded work in my opinion.

Saying d = \sqrt{x^2 + (x^2-3)^2} is the same as writing d = sqrt(x^2-(x^2-3)^2)

-------------------------------------------

Part (b)

Plug in x = 0 and you should find the following

d(x) = \sqrt{x^2 + (x^2-3)^2}\\\\d(0) = \sqrt{0^2 + (0^2-3)^2}\\\\d(0) = \sqrt{(-3)^2}\\\\d(0) = \sqrt{9}\\\\d(0) = 3\\\\

This says that the point (x,y) = (0,3) is 3 units away from the origin (0,0).

-------------------------------------------

Part (c)

Repeat for x = 1

d(x) = \sqrt{x^2 + (x^2-3)^2}\\\\d(1) = \sqrt{1^2 + (1^2-3)^2}\\\\d(1) = \sqrt{1 + (1-3)^2}\\\\d(1) = \sqrt{1 + (-2)^2}\\\\d(1) = \sqrt{1 + 4}\\\\d(1) = \sqrt{5}\\\\d(1) \approx 2.23606797749979\\\\d(1) \approx 2.24\\\\

-------------------------------------------

Part (d)

Graph the d(x) function found back in part (a)

Use the minimum function on your graphing calculator to find the lowest point such that x > 0.

See the diagram below. I used GeoGebra to make the graph. Desmos probably has a similar feature (but I'm not entirely sure). If you have a TI83 or TI84, then your calculator has the minimum function feature.

The red point of this diagram is what we're after. That point is approximately (1.58, 1.66)

This means the smallest d can get is d = 1.66 and it happens when x = 1.58 approximately.

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we multiply the lenght by the number:

4 \frac{1}{3}*5=20+\frac{5}{3}=21\frac{2}{3}

and we subtract this from the original pipe, that is

30\frac{3}{4}-21\frac{2}{3}

we need to bring the two fractions to the same denominator (by multiplying the fraction art in the first by 3 and 4 the second):

30\frac{9}{12}-21\frac{8}{12}=9 \frac{1}{12}

so the correct answer is D!




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Answer:

638 in.²

Step-by-step explanation:

Assuming you need to cover just the surface area of the box with no overlaps, and the shape is a rectangular prism, then you need to find the surface area of a rectangular prism.

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SA = 2(16 + 7)(9) + 2(16)(7)

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