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Kryger [21]
3 years ago
9

(X+2)(X+6) simplify using grouping

Mathematics
2 answers:
kolbaska11 [484]3 years ago
8 0

I dont know ajsnnnsbdjdbsn

Leona [35]3 years ago
6 0
(x+6)(x+2)
Simplifying
(x + 6)(x + 2)

Reorder the terms:
(6 + x)(x + 2)

Reorder the terms:
(6 + x)(2 + x)

Multiply (6 + x) * (2 + x)
(6(2 + x) + x(2 + x))
((2 * 6 + x * 6) + x(2 + x))
((12 + 6x) + x(2 + x))
(12 + 6x + (2 * x + x * x))
(12 + 6x + (2x + x2))

Combine like terms: 6x + 2x = 8x
(12 + 8x + x2)
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Step-by-step explanation:

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A number cube is rolled 360 times, and the results are recorded as follows: 96 ones, 31 twos, 49 threes, 76 fours, 45 fives, and
svet-max [94.6K]
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To the nearest hundredth, what is the value of x?
Anna [14]

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Solve the equation:<br> 64 x 216^x =54^x
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x=1/256

Step-by-step explanation:

hope it helps you

4 0
3 years ago
. An individual wishes to invest $5000 over the next year in two types of investment: Investment A yields 5%, and investment B y
tresset_1 [31]

Answer:

The amount invested at Investment A must be greater than or equal to $2,750

The amount invested at Investment B must be less than or equal to $2,250

Step-by-step explanation:

Let

x -----> the amount invested at Investment A yields 5%

y -----> the amount invested at Investment B yields 8%

we know that

x+y=5,000

x=5,000-y  -----> equation A

x \geq 0.25(5,000)

x \geq \$1,250 -----> inequality B

y \leq 0.50(5,000)

y \leq \$2,250 -----> inequality C

x \geq \frac{1}{2}y -----> inequality D

Substitute equation A in the inequality D and solve for y

5,000-y \geq \frac{1}{2}y

Multiply by 2 both sides

10,000-2y \geq y

Multiply by -1 both sides

-10,000+2y \leq -y

Adds y both sides

-10,000+2y+y \leq 0

-10,000+3y \leq 0

adds 10,000 both sides

3y \leq 10,000

Divide by 3 both sides

y \leq \$3,333.33 -----> inequality E

therefore

<em>Solve for y</em>

we have

y \leq \$2,250 -----> inequality C

y \leq \$3,333.33 -----> inequality E

The solution of inequality C and inequality E is

y \leq \$2,250

For y=2,250

x=5,000-y ----> x=5,000-2,250=2,750

so

x \geq \$2,750 -----> inequality F

<em>Solve for x</em>

we have

x \geq \$1,250 -----> inequality B

x \geq \$2,750 -----> inequality F

The solution of inequality B and inequality F is

x \geq \$2,750

therefore

The amount invested at Investment A must be greater than or equal to $2,750

The amount invested at Investment B must be less than or equal to $2,250

7 0
3 years ago
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