Answer:
second option
Step-by-step explanation:
Given
+ 6x² + 5 = 0
let u = x², then
u² + 6u + 5 = 0 ← in standard form
(u + 1)(u + 5) = 0 ← in factored form
Equate each factor to zero and solve for u
u + 1 = 0 ⇒ u = - 1
u + 5 = 0 ⇒ u = - 5
Change u back into terms of x, that is
x² = - 1 ( take the square root of both sides )
x = ± = ± i ( noting that = i ), and
x² = - 5 ( take the square root of both sides )
x = ± = ± = ± × = ± i
Solutions are x = ± i and x = ± i
Answer:
Number of days starting from T are:-
Tuesday
Thursday
So, number = 2
Number of days in a week = 7
So, probability = 2/7
Hope it helps...!!!
Step-by-step explanation:
Answer:
1) Enlargement
2) Reduction
Step-by-step explanation:
Question 1
200% means double, a factor 2
a) 2(2.5) = 5 inches
it's an enlargement
b) 2(original) = new/on the page
Question 2
a) 0.6(24) = 14.4 inches
Reduction
b) 0.6(original) = new/sketch
<span>An algebraic expression is an expression constructed from a number of constants and variables utilizing algebraic operations. These algebraic operations are addition, subtraction, multiplication, division, and exponentiation. A constant is constant, so its value is unchanged. A variable changes based on the value provided. In the provided example, 2x-1, there are two constants, "2" and "1", and one variable "x." The algebraic operations utilized are multiplication and subtraction. In order to evaluate the value of the algebraic expression, the given value for the variable must be substituted for the variable x, and then the algebraic operations executed to obtain the answer.
For instance, if you were told that the value of x in this case was 2, then you would substitute the value 2 for x and perform the described operations. Remember to follow the order of operations when evaluating an algebraic expression!
2x-1 for x=2
2(2) - 1
4 - 1
3 is the answer.
Remember, even though the multiplication operation is not explicitly stated, it is implied that a constant attached to a variable (termed a coefficient) is multiplied with the value of the variable.</span>