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timurjin [86]
3 years ago
15

Hi help i'll give you a brainliest<3

Mathematics
2 answers:
qaws [65]3 years ago
6 0

11% increase. 182,040-164,000=18,040. 18,040=11% of 182,040

damaskus [11]3 years ago
4 0

Answer:

11% Increase

Step-by-step explanation:

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What is the equation of the line that passes through the point (-4,1) and has a<br> slope of -3/4
Rashid [163]

Answer:

y = -3/4x - 2

Step-by-step explanation:

y = -3/4x + b

1 = (-3/4) × -4 + b

1 = 3 + b

-2 = b

b = -2

y = -3/4x -2

8 0
3 years ago
Write 700/200 as a terminating decimal
Zolol [24]
700/200 as a terminating decimal is 3.5
8 0
3 years ago
The result of which expression will best estimate the actual product
prisoha [69]

Answer:

The answer is,

(-1) \times \frac {1}{2} \times (-1) \times (1)

Step-by-step explanation:

The given product is,

\frac {-4}{5} \times \frac{3}{5} \times \frac{-6}{7} \times \frac {5}{6}

= \frac {12}{35}

\simeq 0.3429 ---------------------(1)

Now, the first product to compare is,

(-1) \times \frac {1}{4} \times (-1) \times (-1)

= - 0.25 ----------------------------(2)

The second product to compare is,

(-1) \times \frac {1}{2} \times (-1) \times (1)

= 0.5 ------------------------(3)

The 3rd product to compare is,

\frac {-4}{2} \times \frac {3}{2} \times \frac{-2}{5} \times \frac {5}{2}

= 3 ----------------------------(4)

The 4th product to compare is,

\frac {-3}{4} \times \frac {-3}{4} \times \frac {-1}{5} \times \frac {1}{2}

= \frac {-9}{160}

= 0.05625 -----------------(5)

Comparing all the values , we get (3) is closest to (1).

Hence, we get, the answer is,

(-1) \times \frac {1}{2} \times (-1) \times (1)

3 0
3 years ago
Evaluate the integral ∫2−1|x−1|dx
defon

I think you might be referring to the definite integral,

\displaystyle \int_{-1}^2|x-1|\,\mathrm dx

Recall the definition of absolute value:

|x| = \begin{cases}x&\text{if }x\ge0\\-x&\text{if }x

Then |x-1|=x-1 if x\ge1, and |x-1|=1-x is x. So spliting up the integral at <em>x</em> = 1, we have

\displaystyle \int_{-1}^2|x-1|\,\mathrm dx = \int_{-1}^1(1-x)\,\mathrm dx + \int_1^2(x-1)\,\mathrm dx

The rest is simple:

\displaystyle \int_{-1}^2|x-1|\,\mathrm dx = \left(x-\dfrac{x^2}2\right)\bigg|_{-1}^1 + \left(\dfrac{x^2}2-x\right)\bigg|_1^2 \\\\ = \left(\left(1-\frac12\right)-\left(-1-\frac12\right)\right) + \left(\left(2-2\right)-\left(\frac12-1\right)\right) \\\\ = \boxed{\frac52}

5 0
3 years ago
A number "n" is at least 4
KIM [24]
At least means that at the lowest or smallest amount, it is that number, which is 4. So, the equation for this would be n≥4
3 0
2 years ago
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