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Virty [35]
2 years ago
15

Will give BRAINLYEST PLZ HELP FAST

Mathematics
2 answers:
Nikolay [14]2 years ago
8 0

Answer:

should be A

Step-by-step explanation:

please give brainliest

kiruha [24]2 years ago
5 0

Answer:

One factor is negative and one factor is positive, so the product will be negative

Step-by-step explanation:

So i'm not sure what the first one is because there's a typo but it should be

One factor is negative and one factor is positive, so the product will be negative. A positive times a negative or vise versa, will always be a negative

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A cylindrical cup is 10 centimeters in height. When filled to the very top, it holds 500 cubic centimeters of water. What is the
Vladimir [108]

Answer:

4

Step-by-step explanation:

the formula for radius is

r=\sqrt{\frac{v}{\pi h } }

so. 500 divided by pi times 10. then square root your final answer. cool. let's get started.

3.14*10 is 31.4, you can do that without thinking.

500/31.4=15.92

\sqrt{}15.92= 3.99, or just 4

the radius is four.

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B5x%2F8y%7D" id="TexFormula1" title="\sqrt[4]{5x/8y}" alt="\sqrt[4]{5x/8y}" al
Furkat [3]

Answer:  \frac{\sqrt[4]{10xy^3}}{2y}

where y is positive.

The 2y in the denominator is not inside the fourth root

==================================================

Work Shown:

\sqrt[4]{\frac{5x}{8y}}\\\\\\\sqrt[4]{\frac{5x*2y^3}{8y*2y^3}}\ \ \text{.... multiply top and bottom by } 2y^3\\\\\\\sqrt[4]{\frac{10xy^3}{16y^4}}\\\\\\\frac{\sqrt[4]{10xy^3}}{\sqrt[4]{16y^4}} \ \ \text{ ... break up the fourth root}\\\\\\\frac{\sqrt[4]{10xy^3}}{\sqrt[4]{(2y)^4}} \ \ \text{ ... rewrite } 16y^4 \text{ as } (2y)^4\\\\\\\frac{\sqrt[4]{10xy^3}}{2y} \ \ \text{... where y is positive}\\\\\\

The idea is to get something of the form a^4 in the denominator. In this case, a = 2y

To be able to reach the 16y^4, your teacher gave the hint to multiply top and bottom by 2y^3

For more examples, search out "rationalizing the denominator".

Keep in mind that \sqrt[4]{(2y)^4} = 2y only works if y isn't negative.

If y could be negative, then we'd have to say \sqrt[4]{(2y)^4} = |2y|. The absolute value bars ensure the result is never negative.

Furthermore, to avoid dividing by zero, we can't have y = 0. So all of this works as long as y > 0.

3 0
2 years ago
HELPPOP PLEASRSGEHDNDBIEISJEp
-Dominant- [34]

Answer:

linear

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Find the radius of a circle with a diameter of 40 in.
Svetllana [295]

Answer:20 In

Step-by-step explanation:

Diameter=40 In

radius=diameter ➗ 2

radius=40 ➗ 2

radius=20 In

8 0
3 years ago
Solve the equation. Round the solution to the nearest tenth . Enter the solution set of the equation . 2P o =P 0 (1.053)^ t
kow [346]

Answer: t= 13.4

Step-by-step explanation:

The given equation is 2P_0=P_0(1.053)^t

To solve this equation for 't', we first divide both sides by P_0, we get

2=(1.053)^t

Taking log on both the sides, we get

\log 2= \log(1.053)^t

Since \log a^b=b\log a

Then,

\log 2= t\log1.053\\\\\Rightarrow0.30103=t(0.02243)\\\\\Rightarrow t=\dfrac{0.30103}{0.02243}\\\\\Rightarrow t=13.4208649131\approx13.4

Hence, the value of t is 13.4.

6 0
3 years ago
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