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3 years ago

Using pemdas what’s the correct solution

Mathematics

2 answers:

Alik [6]3 years ago

5 0

Answer:

the answer is 16/27

Step-by-step explanation:

hope this helps :)

SSSSS [86.1K]3 years ago

4 0

4- 2/3 (4-1/6) divided by 3/4

parenthesis first

4 - 2/3 (3 5/6) divided by 3/4

change to an improper fraction (6*3+5)/6

4 - 2/3 ( 23/6)divided by 3/4

4 - 46/18 divide by3/4

copy dot flip

4 - 46/18 * 4/3

4 - 23/9 * 4/3

4 - 92/27

get a common denominator of 27

4*27/27 -92/27

108/27 - 92/27

16/27

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Simplify the radical expression. Show all your steps. <br><br> √363 - 3√27

siniylev [52]

Answer:

2 sqrt(3)

Step-by-step explanation:

Simplify the following:

sqrt(363) - 3 sqrt(27)

sqrt(27) = sqrt(3^3) = 3 sqrt(3):

sqrt(363) - 33 sqrt(3)

sqrt(363) = sqrt(3×11^2) = 11 sqrt(3):

11 sqrt(3) - 3×3 sqrt(3)

-3×3 = -9:

11 sqrt(3) + -9 sqrt(3)

11 sqrt(3) - 9 sqrt(3) = 2 sqrt(3):

Answer: 2 sqrt(3)

3 0

3 years ago

2. Two puppies together weigh 22 kilograms 300 grams. If one

monitta

Answer:

B = 12800 grams or 12kg 800 grams.

Step-by-step explanation:

Let the two puppies be A and B respectively.

Translating the word problem into an algebraic expression, we have;

A + B = 22kg 300g

A = 9kg 500g

Conversion;

1 Kilograms = 1000 grams.

9kg 500g = 9*1000 + 500 = 9500 grams

22kg 300g = 22*1000 + 300 = 22300 g

Substituting into the above formula, we have;

9500 + B = 22300

B = 22300 - 9500

B = 12800 grams or 12kg 800 grams

6 0

3 years ago

A packing carton in the shape of a triangular right prism shown below. Find the volume of the prism.

Annette [7]

Answer: The volume is 120 $in^3$ .

Step-by-step explanation:

-The volume formula for a triangular prism is:

(Height × Base × Length) /2

-So, you put the height, base, and length:

(4 × 6 × 10)

-Then, you solve:

(4 × 6 × 10)

(24 × 10)

240

-Divide 240 by 2:

240 ÷ 2

120

Therefore, the volume of a Triangular Prism is $120in^3$ .

3 0

3 years ago

What is 35 X (5 +150)=

ololo11 [35]

Answer: 5425

Step-by-step explanation:

7 0

3 years ago

Can anyone help me with this? im confused

kvasek [131]

Answer:

1,2,3 and 6 are similar triangles by AA similarity

Step-by-step explanation:

1) ∠DEC ≅ ∠FEG {Vertically opposite angles}

DC // GF

∠ECD ≅ ∠EGF {Alternate interior angles}

∠EDC ≅ ∠EFG {Alternate interior angles}

ΔDEC & ΔFEG are similar triangles by AA similarity

2)MN // QP

∠LQP ≅ ∠QMN {Corresponding angles }

∠LPQ ≅ ∠PNM {Corresponding angles}

ΔLQP & ΔLMN are similar triangles by AA similarity

3) In ΔSYE ,

∠S = 180 - 90 - 39

∠S = 51°

In ΔCHW,

∠H = 180 - 51 - 90

∠H = 39

ΔSYE and ΔCHW

∠S ≅ ∠W = 51°

∠Y ≅ ∠C = 90°

∠E ≅∠H = 39°

ΔSYE & ΔWCH are similar triangles by AA similarity

6) ∠P ≅ ∠Z {Given}

∠PXQ ≅∠ZXY {Vertically opposite angles}

ΔPXQ & ΔZXY are similar triangles by AA similarity

5 0

2 years ago