Circumference: 2πr C=18 so r= 18/2π= 9π
Arc length = rθ 6=(9π)θ θ=6/9π
Convert to degrees by multiplying by 180/π
6/9π x 180/π = 120 degrees
The answer should be B.
5(6.86x)
Answer:
In words the answer is between t=0 and t=2.
In interval notation the answer is (0,2)
In inequality notation the answer is 0<t<2
Big note: You should make sure the function I use what you meant.
Step-by-step explanation:
I hope the function is h(t)=-16t^2+32t because that is how I'm going to interpret it.
So if we can find when the ball is on the ground or has hit the ground (this is when h=0) then we can find when it is in the air which is between those 2 numbers.
0=-16t^2+32t
0=-16t(t-2)
So at t=0 and t=2
So the ball is in the air between t=0 and t=2
Interval notation (0,2)
Inequality notation 0<t<2
There is little context to go off of but the answer should be variable
You just need to use your test-taking skill to eliminate the wrong answers here.
There is no such thing as a "Congruent Angles Postulate," so the last two choices can be eliminated.
The AA Similarity Postulate refers to triangles, not angles, so the second choice can be eliminated.
That only leaves the (correct) first choice.
