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IgorLugansk [536]
3 years ago
6

Solve: 2(4v-9) - (3v-11) =-52

Mathematics
1 answer:
inysia [295]3 years ago
7 0

Answer:

v = -9

Step-by-step explanation:

2(4v - 9) - (3v - 11) = -52

8v - 18 - (3v - 11) = -52

8v - 18 -3v + 11 = -52

5v - 7 = -52

<em>+ 7 | + 7</em>

5v = -45

<em>/5</em>

v = -9

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Answer:

0.281 = 28.1% probability a given player averaged less than 190.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

A bowling leagues mean score is 197 with a standard deviation of 12.

This means that \mu = 197, \sigma = 12

What is the probability a given player averaged less than 190?

This is the p-value of Z when X = 190.

Z = \frac{X - \mu}{\sigma}

Z = \frac{190 - 197}{12}

Z = -0.58

Z = -0.58 has a p-value of 0.281.

0.281 = 28.1% probability a given player averaged less than 190.

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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