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IgorLugansk [536]
2 years ago
6

Solve: 2(4v-9) - (3v-11) =-52

Mathematics
1 answer:
inysia [295]2 years ago
7 0

Answer:

v = -9

Step-by-step explanation:

2(4v - 9) - (3v - 11) = -52

8v - 18 - (3v - 11) = -52

8v - 18 -3v + 11 = -52

5v - 7 = -52

<em>+ 7 | + 7</em>

5v = -45

<em>/5</em>

v = -9

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Can someone help me solve this step by step? tyyyy
vlabodo [156]

Answer:

x=4/7

Step-by-step explanation:

6 - 2/3(x+5) = 4x

First I want to clear the fraction so I will multiply everything by 3

3*6 -3* 2/3(x+5) = 3*4x

18 - 2(x+5) =12x

Distribute

18 - 2x-10 =12x

Combine like terms

8 -2x = 12x

Add 2x to each side

8 -2x+2x =12x+2x

8 = 14x

Divide each side by 14

8/14 =14x/14

8/14=x

Divide top and bottom by 2

4/7=x

8 0
3 years ago
Please answer this ASAP
valkas [14]

Answer:

x = 2

Step-by-step explanation:

First, let's write out our equation:

2x-4=6-3x

I want to isolate x on one side, so first, I'll add 4 to both sides to remove the -4 from next to 2x:

2x-4+4=6-3x+4\\2x=-3x + 10

Notice that I combined like terms with the -4 and 4 (to get 0) and the 6 and 4 on the right side (to get 10). Next, I'll add 3x to both sides:

2x + 3x = -3x + 3x + 10

And then I'll add like terms:

5x=10

Now, all we have to do is divide both sides by 5:

5x/5=10/5\\x=2

And there's our answer. Hopefully that's helpful! :)

6 0
2 years ago
<img src="https://tex.z-dn.net/?f=%5Cleft%28%5Csqrt%7B2%7D%2B1%5Cright%29%5Cleft%285%2B%5Csqrt%7B2%7D%5Cright%29" id="TexFormula
dsp73
<h3>Solution:</h3>

( \sqrt{2}  + 1)(5 +  \sqrt{2}) \\  =  \sqrt{2}  (5 +  \sqrt{2} ) + 1(5 +  \sqrt{2} ) \\  = 5 \sqrt{2}  + 2 + 5 +  \sqrt{2}  \\  = 7 + 6 \sqrt{2}

<h3>Answer:</h3>

7 + 6√2

5 0
2 years ago
Read 2 more answers
Graph f(x)=-2x^2-12x-21
ELEN [110]

Step-by-step explanation:

First, find the vertex. The x coordinate is -b/2a, or 12/-4=-3. Plug this back in to get -18+36-21 or -3, so the vertex is (-3, -3). Now, slowly make the x -2, -1, 0, 1, on and on. Because parabolas are symmetric along the vertex, they will have the same values as -4, -5, -6, on and on.

5 0
3 years ago
You are flying a kite on a line that is 350 feet long. Let's suppose the line is perfectly straight (it never really is) and it
aliina [53]

Answer:

We can think that the line of the kite is the hypotenuse of a triangle rectangle, and the altitude is one of the cathetus of the triangle.

And we know that it makes an angle of 65° with the horizontal (i guess this is measured between the hypotenuse and the horizontal adjacent to the kite.

This angle is complementary to the top angle of our triangle rectangle, such that A + 65° = 90°

A = 90° - 65° = 25°

Then the altitude of the kite is the adjacent cathetus to this angle.

We can use the relation:

sin(A) = Adjacent cathetus/hypotenuse.

Sin(25°) = X/350ft

Sin(25°)*350ft = X = 147.9m

4 0
3 years ago
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