Answer:
B) 25x + 50, where x is the number of hours .
Solution:
Let x be the number of hours editor takes to edit 3 essays.
The editor is paid $25 an hour .
Amount earned in x hours = 25x
Additional bonus given after edition of three essays = $50.
Total amount earned by the editor = 25x+50
The right option is :
B) 25x + 50, where x is the number of hours
you can use integration
I could have done It by typing it here is hectic. you can inbox you email so that I send you scanned answer
Answer:
![Width = 20\ in](https://tex.z-dn.net/?f=Width%20%3D%2020%5C%20in)
![Area = 400\ in^2](https://tex.z-dn.net/?f=Area%20%3D%20400%5C%20in%5E2)
Step-by-step explanation:
Given
See attachment for kite dimension
Required
Determine the width and the area
From the attachment, the height of the kite is:
![Height = 31\ in + 9\ in](https://tex.z-dn.net/?f=Height%20%3D%2031%5C%20in%20%2B%209%5C%20in)
![Height = 40\ in](https://tex.z-dn.net/?f=Height%20%3D%2040%5C%20in)
The width which is half the height is:
![Width = \frac{1}{2} * Height](https://tex.z-dn.net/?f=Width%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%2A%20Height)
![Width = \frac{1}{2} * 40\ in](https://tex.z-dn.net/?f=Width%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%2A%2040%5C%20in)
![Width = 20\ in](https://tex.z-dn.net/?f=Width%20%3D%2020%5C%20in)
The area is:
![Area = \frac{Height * Width}{2}](https://tex.z-dn.net/?f=Area%20%3D%20%5Cfrac%7BHeight%20%2A%20Width%7D%7B2%7D)
![Area = \frac{40\ in * 20\ in}{2}](https://tex.z-dn.net/?f=Area%20%3D%20%5Cfrac%7B40%5C%20in%20%2A%2020%5C%20in%7D%7B2%7D)
![Area = 40\ in * 10\ in](https://tex.z-dn.net/?f=Area%20%3D%2040%5C%20in%20%2A%2010%5C%20in)
![Area = 400\ in^2](https://tex.z-dn.net/?f=Area%20%3D%20400%5C%20in%5E2)
Answer:
55
Step-by-step explanation:
This is 55 because you need to make a sum of 180 when making a line and 125+55=180
Answer:
(1.5,0)
(.5,0)
Step-by-step explanation:
Quadratic formula below
We first need to move everything to one side of the equation
4x²-8x+3=0
Then plug everything in
(8±√(-8²-4*4*3))/(2*4)
(8±√16)/8
To calculate the ± we need to do when where it's adding and then negative
we have
(8+4)/8=3/2
and hten
(8-4)/8=1/2