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4 years ago

If P(E)=.14 what is P(E')

1 answer:

7 0

<span>By complement rules, P(E') + P(E) = 1

So 1 - P(E) = </span>P(E')<span> = 1 - 0.14 = 0.86

Final answer: </span>P(E') = 0.86

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Use a protractor to find the angle measure

scoray [572]

164 degrees

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3 years ago

Read 2 more answers

Tim earns $280 every week in his paycheck. If he saves 10% of each

Alex73 [517]

Answer:

336

Step-by-step explanation:

10 times 280 over 100 equals 28 time 12 equals 336

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4 years ago

What is the solution to the equation x + 11 = 57? (Input a whole number only.) Numerical Answers Expected! Answer for Blank 1:

tigry1 [53]

Rearrange to get x on its own on one side of the equation:
x = 57 - 11
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3 years ago

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On a particular flight, the airline's income was $95,280 for a jumbo jet carrying 290 passengers. If a first-class ticket costs

SIZIF [17.4K]

Answer:

30 first-class tickets were sold and 260 coach tickets were sold.

Step-by-step explanation:

Let a first-class ticket be represented by f and let a coach ticket be represented by c.

On a particular flight, a jumbo jet was carrying 290 passengers. So, the sum of the first-class tickets and coach tickets must sum to 290:

$f+c=290$

The total income was $95,280. Therefore:

$680f+288c=95280$

We can now solve the system of equations. First, we can simplify the second equation by dividing everything by 8:

$85f+36c=11910$

From the first equation, we can subtract f from both sides:

$c=290-f$

Substitute:

$85f+36(290-f)=11910$

Distribute:

$85f+10440-36f=11910$

Simplify:

$49f=1470$

So:

$f=30$

From the previous equation:

$c=290-f$

Substitute:

$c=290-30=260$

30 first-class tickets were sold and 260 coach tickets were sold.

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3 years ago

Please help with these two questions above!!! Brainliest will be given.

vovikov84 [41]

Answer:

In both above questions, correct option is (D).

#$#THANK YOU #$#

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3 years ago