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Verdich [7]
3 years ago
10

(6 x 10^2)\(3x10^-5)

Mathematics
2 answers:
Bingel [31]3 years ago
6 0

the answer is 2 x 10^7 :D

quack quack quack (hopefully this helps)

maksim [4K]3 years ago
3 0

Answer: 20,000,000 or 2 × 10^7

Step-by-step explanation:

(6 × 10²) ÷ (3 × 10^-5)

(6 × 100) ÷ (3 × 0.00001

)

600 ÷ 0.00003

20,000,000

or

2 × 10^7

Hope this helped!

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In the warmer months, Ms.Selwa likes to run to school to get in her daily exercise. She can run 1/6 of a kilometer in a minute.
Lerok [7]

Answer:

3 minutes

Step-by-step explanation:

If Ms. Selwa can run 1/6 of a kilometer in a minute, she can run 3/6 of a kilometer in 3 minutes.

This is because 1/6 times 3 equals 3/6, which is the distance of the school from her home.

So, it will take Ms. Selwa 3 minutes to run to school.

8 0
3 years ago
A. 34cm^3<br> b. 1560cm^3<br> c. 104cm^3<br> d 676cm^3
Vanyuwa [196]

Answer:

676 cubic cm choice d

Step-by-step explanation:

Base area times height gets volume

Base area =  (1/2)*13 * 8  =  52 sq. cm   (area of the right triangle)

height = 13 cm  here

Volume = 13 cm * 52 sq. cm = 676 cubic cm

4 0
3 years ago
The dinner bill came to $72.48, and Julio tipped the waiter 15%. What is the total price of dinner?​
balu736 [363]

Answer:

It is 83.35 Unless your rounding up then it is 84 dollars

Step-by-step explanation:

5 0
3 years ago
Ill mark btainlist pllssss helpp
Hatshy [7]

Answer:

1cm-----80000m

1cm-----8000000cm

1cm×3.275-----80km×3.275

3.275cm

3 0
3 years ago
Given: ∆ABC, m∠C = 90° CB = 8, m∠B = 38º Find the area of a circumscribed circle. Find the area of the inscribed circle.
vitfil [10]

Answer:

Circumscribed circle: Around 80.95

Inscribed circle: Around 3.298

Step-by-step explanation:

Since C is a right angle, when the circle is circumscribed it will be an inscribed angle with a corresponding arc length of 2*90=180 degrees. This means that AB is the diameter of the circle. Since the cosine of an angle in a right triangle is equivalent to the length of the adjacent side divided by the length of the hypotenuse:

\cos 38= \dfrac{8}{AB} \\\\\\AB=\dfrac{8}{\cos 38}\approx 10.152

To find the area of the circumscribed circle:

r=\dfrac{AB}{2}\approx 5.076 \\\\\\A=\pi r^2\approx 80.95

To find the area of the inscribed circle, you need the length of AC, which you can find with the Pythagorean Theorem:

AC=\sqrt{10.152^2-8^2}\approx 6.25

The area of the triangle is:

A=\dfrac{bh}{2}=\dfrac{8\cdot 6.25}{2}=25

The semiperimeter of the triangle is:

\dfrac{10.152+6.25+8}{2}\approx 24.4

The radius of the circle is therefore \dfrac{25}{24.4}\approx 1.025

The area of the inscribed circle then is \pi\cdot (1.025)^2\approx 3.298.

Hope this helps!

6 0
4 years ago
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