Answer:
65%
Step-by-step explanation:
Step-by-step explanation:
let us give all the quantities in the problem variable names.
x= amount in utility stock
y = amount in electronics stock
c = amount in bond
“The total amount of $200,000 need not be fully invested at any one time.”
becomes
x + y + c ≤ 200, 000,
Also
“The amount invested in the stocks cannot be more than half the total amount invested”
a + b ≤1/2 (total amount invested),
=1/2(x + y + c).
(x+y-c)/2≤0
“The amount invested in the utility stock cannot exceed $40,000”
a ≤ 40, 000
“The amount invested in the bond must be at least $70,000”
c ≥ 70, 000
Putting this all together, our linear optimization problem is:
Maximize z = 1.09x + 1.04y + 1.05c
subject to
x+ y+ c ≤ 200, 000
x/2 +y/2 -c/2 ≤ 0
≤ 40, 000,
c ≥ 70, 000
a ≥ 0, b ≥ 0, c ≥ 0.
Answer:
x=1
Step-by-step explanation:
For algebra always start by rewriting it.
4+x+2-2x=5
Then ask yourself is there any like terms we can combine, and here yes there is. 4 and 2 and x and -2x. Now lets combine them and rewrite.
6-x=5
Now lets get x alone and the quickest way is to subtract 6 to the other side
6-x=5
-6 -6
-x=-1
Now the two negatives cancel out as you would divide both sides by the coefficient -1 to get positive x alone. We can make this easier by just canceling out the negatives.
Your answer is
x=1
The answer is 49 because it is
Answer:
x ≤ 2
Step-by-step explanation:
2 red rose cost $ 18
x flowers cost $ 11x
"At most " means ≤.
11x + 18 ≤ 40
11x ≤ 40 - 18
11x ≤ 22
x ≤ 2
