What is the product 7000 ×50 written as the product of a whole number and a power of 10?

Mathematics

1 answer:

SpyIntel [72]3 years ago

4 0

Answer:

35 × $10^{4}$

Step-by-step explanation:

7000= 7 × $10^{3}$

50= 5 × 10

So,

7000 × 50 =

35 × $10^{4}$

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Find the product. If the result is negative, enter "-". If the result is positive, enter "+". -7(- a2 ) 2 ( -b3 ).

m_a_m_a [10]

Answer:

The product is positive, thus it is $\bold{+7a^4b^3}$

Step-by-step explanation:

The full question in proper notation is:

"Find the product. If the result is negative, enter "-". If the result is positive, enter "+".

$-7(-a^2)^2(-b^3)$ "

We have to work with it using Order of operations know as well as PEMDAS, thus expression inside parenthesis go first and exponents.

On this expression we have to work with exponents

$(-a^2)^2 = (-a^2)(-a^2) =a^4$

Thus we get

$-7(-a^2)^2(-b^3)=-7a^4(-b^3)$

Lastly we can work with multiplication and remembering that the multiplication of two negative signs becomes positive.

$-7(-a^2)^2(-b^3)=7a^4b^3$

So the final simplified expression is $\bold{7a^4b^3}$

5 0

3 years ago

Read 2 more answers

A probability experiment is conducted in which the sample space of the experiment is upper s equals { 1 comma 2 comma 3 comma 4

Softa [21]

You can think of this experiment as follows: you have to select a random number between 1 and 15, where each number is equally likely to appear.

Player A wins if 3,4,5 or 6 are picked.

Player B wind is 10,11 or 12 are picked.

Two events are said to be mutually exclusive if they cannot happen at the same time. So, in our metaphor, the question is: can we pick a particular number, so that both players win simultaneously?

The question is no, because if player A wins, we have picked 3,4,5 or 6, and player B wins with none of these numbers.

Similarly, if player B wins, we have picked 10, 11 or 12, and player A wins with none of these numbers.

So, the two events cannot occur simultaneously.

If you want to be more formal, since the events are subset of the sample space, two events are mutually exclusive if their intersection is the empty set, and this is the case:

$A \cap B = \{3,4,5,6\}\cap\{10,11,12\} = \emptyset$