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2 years ago

Line equations from point/slope

Mathematics

1 answer:

babunello [35]2 years ago

8 0

Answer:

The answer is

$y = \frac{1}{4} x + 3$

Step-by-step explanation:

Plug in and solve the equation. We are trying to find the y-intercept:

$y= \frac{1}{4}x + b \\ 2 = \frac{1}{4} ( - 4) + b \\ 2 = - 1 + b \\ \frac{ + 1 = + 1 \: \: \: \: \: \: \: \: }{3 = b}$

We found the y-intercept, so now we plug it in it's right full spot in the formula.

$y = \frac{1}{4} x + 3$

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What is this answer i didn’t go to school for it

Oksana_A [137]

Answer:

-2 -1,1, and 2 only

Step-by-step explanation:

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3 years ago

Find a 95% confidence interval for the mean auditory response time for subjects with a visual response time of 200 ms. The 95% c

Sveta_85 [38]

Answer:

hello your question is incomplete attached below is the complete question

answer : ( 184.019 , 206.219 )

Step-by-step explanation:

The 95% confidence interval for the mean auditory response time for subjects with a visual response time of 200 ms can be calculated using this relationship below

y = Bo + B1 ( 200 ) = 195.118621 , sy =

hence a 95% confidence interval = 195.118621 ± 2.306( 4.813492) i.e. ( 184.019 , 206.219 )

attached below is the remaining part the solution

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3 years ago

The sum of 13 and twice a number

Setler79 [48]

This would be 13+2x because if x is the number, then 2 times it would be 2x and the sum means addition so it would be 13+2x

7 0

3 years ago

A cup of coffee contains about 100 mg of caffeine. Caffeine is metabolized and leaves the body at a continuous rate of about 12%

Mamont248 [21]

Answer:

a. $A = C_{0}(1-x)^t\\x: percentage\ of \ caffeine\ metabolized\\$

b. $\frac{dA}{dt}= -11.25 \frac{mg}{h}$

Step-by-step explanation:

First, we need tot find a general expression for the amount of caffeine remaining in the body after certain time. As the problem states that every hour x percent of caffeine leaves the body, we must substract that percentage from the initial quantity of caffeine, by each hour passing. That expression would be:

$A= C_{0}(1-x)^t\\t: time \ in \ hours\\x: percentage \ of \ caffeine\ metabolized\\$

Then, to find the amount of caffeine metabolized per hour, we need to differentiate the previous equation. Following the differentiation rules we get:

$\frac{dA}{dt} =C_{0}(1-x)^t \ln (1-x)\\\frac{dA}{dt} =100*0.88\ln(0.88)\\\frac{dA}{dt} =-11.25 \frac{mg}{h}$

The rate is negative as it represents the amount of caffeine leaving the body at certain time.

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3 years ago

Ok this is a long one, so any help would mean the world, even if you only do part of it.

jeka94

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3 years ago