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zubka84 [21]
2 years ago
13

Line equations from point/slope

Mathematics
1 answer:
babunello [35]2 years ago
8 0

Answer:

The answer is

y =  \frac{1}{4} x + 3

Step-by-step explanation:

Plug in and solve the equation. We are trying to find the y-intercept:

y=  \frac{1}{4}x  + b \\  2 =  \frac{1}{4} ( - 4) + b \\ 2 =  - 1 + b \\  \frac{ + 1 =  + 1  \:  \:  \:  \:  \:  \:  \:  \: }{3 = b}

We found the y-intercept, so now we plug it in it's right full spot in the formula.

y =  \frac{1}{4} x + 3

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2d[d²(d+3) -9(d+3)]
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d²-9 can still be factored because it is the difference of two squares:

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3 years ago
At a local print shop 8 copies can be made for $4. At this rate how many copies can be made for $6
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Answer:

A copy machine can make 250 copies in 4 minutes. Represent the constant rate of change in copies per minute. answer choices. 125 copies per minute

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skad [1K]

Step-by-step explanation:

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1 year ago
the lenght of a room is twice its breadth and thrice its height if the cost of carpeting the floor at rs 80 per sq metre is rs 9
noname [10]

Answer:

Let's define the variables:

L = length of the room

B = breadth of the room

H = height of the room.

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A = L*B

Then the area of the floor of the room is:

A = L*B

and L = 2*B, if we replace that, we get:

A = (2*B)*B

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Now, we know that the cost of carpeting the floor is $80 per m^2

And the total cost was $9000

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A = ($9000)/($80)  m^2

A = 112.5 m^2

With this, we can find the value of B.

A = 112.5 m^2 = 2*B^2

B = √( 112.5/2) m = 7.5 m

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Now, we will have two walls with an area of:

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Then the total area of the four walls plus the ceiling is:

A' = 2*(37.5m^2) + 2*( 75m^2) + 112.5 m^2

A' = 337.5 m^2

And we know that for each m^2, the cost of plastering is $35

Then for 337.5 m^2, the cost will be 337.5 times $35

Cost = (337.5)*$35 = $11,812.50

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Can’t see a picture or can you send one so I can see the problem
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