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djyliett [7]
2 years ago
10

Write two expressions with the solution set of {5}, (make it simple)

Mathematics
1 answer:
Montano1993 [528]2 years ago
4 0
I have no idea ☠️ i just need to answer questions to be able to ask questions
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FIRST CORRECT ANSWER WILL GET BRANLIEST!
il63 [147K]
Greatest common factor (or denominator) is 6,
least common multiple is 180

hmm
(note: I spent like 30 mins trying to use a math only of finding the values but it didn't work so I did a  force brute and elimination method explained below)


so
a and b must be multiples of 6
so list all the multiples of 6
wait
180=6*30 and 30's factors are 1,2,3,5,6,10,15,30 so only list the numbers that are the result of multiplying 6 and any of those numbers in that list (so we can have the lcm of 180)
so
6*1=6
6*2=12
6*3=18
6*5=30
6*6=36
6*10=60
6*15=90
6*30=180
these are our possible candidates for the 2 numbers
now we must find the pair that has a GCD of only 6

doing the math is long and tedious so do it yourself (trial and error)

we see that our choices that fulfill both requirements (GCD of 6 and LCM of 180) are
90&12
60&18
30&36
sum them to find the least one

90+12=102
60+18=78
30+36=66

the least possible sum is 66
3 0
3 years ago
Jamal is shopping with a gift card he received for his birthday. After he purchases two T- shirts the gift card balance has drop
Ede4ka [16]

Answer:

14.99

Step-by-step explanation:

20.02=50-2t

20.02-50= -2t

-29.98= -2t


3 0
3 years ago
How do u write 2/400=2/400÷4/4=0.5/100= as a percent
Vlad1618 [11]

Answer:

0.5%.

Step-by-step explanation:

The definition of percent is  'parts per 100'.

0.5 / 100 = 0.5 percent.

7 0
3 years ago
Find the solution of the differential equation that satisfies the given initial condition. dy/dx=x/y , y(0)=-1
Charra [1.4K]

Separating variables, we have

\dfrac{dy}{dx} = \dfrac xy \implies y\,dy = x\,dx

Integrate both sides.

\displaystyle \int y\,dy = \int x\,dx

\dfrac12 y^2 = \dfrac12 x^2 + C

Given that y(0)=-1, we find

\dfrac12 (-1)^2 = \dfrac12 0^2 + C \implies C = \dfrac12

Then the particular solution is

\dfrac12 y^2 = \dfrac12 x^2 + \dfrac12

y^2 = x^2 + 1

y = \pm\sqrt{x^2 + 1}

and because y(0)=-1, we take the negative solution to accommodate this initial value.

\boxed{y(x) = -\sqrt{x^2+1}}

7 0
2 years ago
A portion of the graph of f(x) = −x2 − 2x + 8 is shown. Which of the following describes all solutions for f(x)?
Naily [24]

Answer:

(x,-x^2-2x+8) where −5 ≤ x ≤ 3

Step-by-step explanation:

The given function is f(x)=-x^2-2x+8.

We want to select the option that describes all the solutions to the parabola.

The domain of the parabola is −5 ≤ x ≤ 3.

This means that  any x=a on −5 ≤ x ≤ 3 that satisfies (a,f(a)), is a solution.

This can be rewritten as (a,-a^2-2a+8)

Therefore for x belonging to −5 ≤ x ≤ 3, all solutions are given by:

(x,-x^2-2x+8) where −5 ≤ x ≤ 3.

7 0
3 years ago
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