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Leto [7]
3 years ago
7

Who wanna get 100pts. free? say yes and i'll ask a 100 point question

Mathematics
2 answers:
Nataly_w [17]3 years ago
8 0

Answer: yes pls and thank you very much i would really need it i appreciate it

Step-by-step explanation:

fgiga [73]3 years ago
7 0

Answer:

I do

Step-by-step explanation:

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Your answer is \frac{23}{99}

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at a particular high school, 42% of the students participate in sports and 25% of the students participate in drama. if 53% of t
baherus [9]

The probability that a student participates in both sports and drama is 0.14.

<h3>What is the formula for P(AUB), where A and B are any two events?</h3>

If A and B are any two events, then the probability of the joint event (A\cup B) is given by the following formula: P(A\cup B)=P(A)+P(B)-P(A\cap B)

Given that 42% of the students participate in sports and 25% of the students participate in drama and 53% of the students participate in either sports or drama.

Suppose S denotes that "a student participates in sports" and D denotes that "a student participates in drama".
So, we have P(S)=\frac{42}{100}=0.42, P(D)=\frac{25}{100}=0.25, P(S\cup D)=\frac{53}{100}=0.53.

We want to find the probability that a student participates in both sports and drama i.e., we want to find P(S\cap D).

By the above formula, we obtain:

P(S\cup D)=P(S)+P(D)-P(S\cap D)\\\Longrightarrow P(S\cap D)=P(S)+P(D)-P(S\cup D)\\\Longrightarrow P(S\cap D)=0.42+0.25-0.53\\\therefore P(S\cap D)=0.14=\frac{14}{100}

Therefore, the probability that a student participates in both sports and drama is 0.14.

To learn more about probability, refer: brainly.com/question/24756209

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Second one

Step-by-step explanation:

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