There would be 5 buses and 9 extra seats because 5 x 52 is 260 and you need 251 and there would be 9 extra seats
A.) To find the maximum height, we can take the derivative of h(t). This will give us the rate at which the horse jumps (velocity) at time t.
h'(t) = -32t + 16
When the horse reaches its maximum height, its position on h(t) will be at the top of the parabola. The slope at this point will be zero because the line tangent to the peak of a parabola is a horizontal line. By setting h'(t) equal to 0, we can find the critical numbers which will be the maximum and minimum t values.
-32t + 16 = 0
-32t = -16
t = 0.5 seconds
b.) To find out if the horse can clear a fence that is 3.5 feet tall, we can plug 0.5 in for t in h(t) and solve for the maximum height.
h(0.5) = -16(0.5)^2 + 16(-0.5) = 4 feet
If 4 is the maximum height the horse can jump, then yes, it can clear a 3.5 foot tall fence.
c.) We know that the horse is in the air whenever h(t) is greater than 0.
-16t^2 + 16t = 0
-16t(t-1)=0
t = 0 and 1
So if the horse is on the ground at t = 0 and t = 1, then we know it was in the air for 1 second.
Answer:12ft
Step-by-step explanation:
The generic equation of a line is:
y-yo = m (x-xo)
Where,
(xo, yo): It's an ordered pair either.
m: is the slope of the line.
We observe that for a point (xo, yo) infinite lines with different slope m can pass.
Answer:
The conclusion is that for the ordered pair (xo, yo) can pass infinite lines that satisfy:
y-yo = m (x-xo)
Answer:
First, do 4x*4x. then,16x*16x. next, 64x*64x. and,256x*256x. answer:1024x. Divide 1024x by 8x. answer to that is 128.
