Consider the example
(3x+5) - (x-10)
When we subtract off the (x-10), we are basically subtracting off x and also subtracting off -10. This is the same as adding on 10 because -(-10) = 10
So we would have these steps
(3x+5)-(x-10)
3x+5-x+10
2x+15
Often students forget to distribute the negative all the way through and would have 3x+5-x-10 as an incorrect step. You need to multiply that -1 through to each term, so that's why the distributive property is used.
Ok, here is what I got:
<span>9/20 is .45 so D is right for sure. C is also correct since the remaining % is 55 ( meaning the percent you won't win) this is also the same as A which is 11/20 or .55. again meaning that .55 is the probability that you won't win. I hope this helps!</span>
Answer:
Option (c) is correct.
Step-by-step explanation:
Given equation is :
The equation can be solved for a as follows :
Step 1.
Cross multiply the given equation
Step 2.
Now subtract b on both sides
3s-b = a+b+c-b
3s-b = a+c
Step 3.
Subtract c on both sides
3s-b-c=a+c-c
⇒ a=3s-b-c
The statement that is true for Darpana is " In step 3, she needed to subtract c rather than divide".
Answer: B) 3+y+3
This can be simplified to y+6, but the current un-simplified expression has 3 terms.
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Explanation:
Terms are separated by a plus sign. If you had something like 10x-5y, then you would write that as 10x+(-5y) showing that 10x and -5y are the two terms.
Choices A and C, xy and 6y respectively, have one term each. They are considered monomials. Mono = one, nomial = name.
Choice D is the product of the constant 3 and the binomial y+3. Binomials have two terms.
Only choice B has three terms, though we can simplify it down to two terms. I have a feeling your teacher doesn't want you to simplify it.
In a symmetric histogram, you have the same number of points to the left and to the right of the median. An example of this is the distribution {1,2,3,4,5}. We have 3 as the median and there are two items below the median (1,2) and two items above the median (4,5).
If we place another number into this distribution, say the number 5, then we have {1,2,3,4,5,5} and we no longer have symmetry. We can fix this by adding in 1 to get {1,1,2,3,4,5,5} and now we have symmetry again. Think of it like having a weight scale. If you add a coin on one side, then you have to add the same weight to the other side to keep balance.
