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ExtremeBDS [4]
2 years ago
8

Can you please help me with this reverse percentage?

Mathematics
1 answer:
ratelena [41]2 years ago
7 0

Answer:

39785

Step-by-step explanation:

or,40596×2÷100=811

or,40596-811=39785

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What is the value of a? Blank units
Damm [24]

Answer:

289

a^2 x b^2 = c^2

a = 8 b= 15 c = s

64 + 225 = 289

square root 289 = 17

4 0
3 years ago
Explain how the distance formula can prove Pythagoras' Theorem. In your
Paul [167]

Answer:

Given a triangle ABC, Pythagoras' Theorem shows that:

c^2=a^2+b^2

Thus,

c = \sqrt{a^2+b^2}

The distance formula, gives an equivalent expression based on two points at the end of the hypotenuse for a triangle.

d^2 = (x_{2} -x_{1})^2 + (y_{2} -y_{1})^2

d = \sqrt{(x_{2}-x_{1})^2 +  (y_{2} -y_{1})^2 }

Therefore when given the hypotenuse with endpoints at

(x_{1}, y_{1})  and {(x_{2}, y_{2})

We know that the third point of the right triangle will be at

(x_{2}, y_{1})

and that the two side lengths will be defined by the absolute values of:

(x_{2} - x_{1}) = a

(y_{2} - y_{1}) = b

8 0
2 years ago
2.3,2 4/5, 2.6 from least to greatest
Alex777 [14]
Hello there! 

Least to greatest of these problem

For the fractions you can simplify it make it easier for you to solve these types of problems

Anyhow! 

Let's find our answer, shall we? 

2.3 = 2.3 \\ \\  2\frac{4}{5} =  \frac{14}{5}  =  2.8 \\ \\ 2.6 = 2.6
 
Our answer: 2.3 \\ 2.6 \\  2\frac{4}{5}
4 0
3 years ago
Show work please.<br><br> solve system of equations using matrices.
nadya68 [22]

Answer:

(t, t -1, t)

Step-by-step explanation:

You have three unknowns but only 2 equations, so you can't really SOLVE this...you can get a solution with a variable still in it (I forget what this is called.  I think it refers to infinite many solutions).  Here's how it works:

Set up your matrix:

\left[\begin{array}{ccc}1&-2&1\\2&-1&-1\\\end{array}\right] \left[\begin{array}{ccc}2\\1\\\end{array}\right]

You want to change the number in position 21 (the 2 in the scond row) to a 0 so you have y and z left.  Do this by multiplying the top row by -2 then adding it to the second row to get that 2 to become a 0.  Multiplying in a -2 to the top row gives you:

\left[\begin{array}{ccc}-2&4&-2\\2&-1&-1\\\end{array}\right]\left[\begin{array}{ccc}-4\\1\\\end{array}\right]

Then add, keeping the first row the same and changing the second to reflect the addition:

\left[\begin{array}{ccc}-2&4&-2\\0&3&-3\\\end{array}\right] \left[\begin{array}{ccc}-4\\-3\\\end{array}\right]

The second equation is this now:

3y - 3z = -3.  Solving for y gives you y = z - 1.  Let's let z = t (some random real number that will make the system true.  Any number will work.  I'll show you at the end.  Just bear with me...)

lf z = t, and if y = z - 1, then y = t - 1.  So far we have that y = t - 1 and z = t.  Now we solve for x:

From the first equation in the original system,

x - 2y + z = 2.  Subbing in t - 1 for y and t for z:

x - 2(t - 1) + t = 2.  Simplify to get

x - 2t + 2 + t = 2  and  x - t = 0, and x = t.  So the solution set is (t, t - 1, t).  Picking a random value for t of, let's say 2, sub that in and make sure it works.  If:

x - 2y + z = 2, then t - 2(t - 1) + t = 2 becomes t - 2t + 2 + t = 2, and with t = 2, 2 - 2(2) + 2 + 2 = 2.    Check it:  2 - 4 + 4 = 2 and 2 = 2.  You could pick any value for t and it will work.

6 0
3 years ago
I need help
Nadusha1986 [10]

Answer:

f(g(x)) = 4x² - 12x + 9

Step-by-step explanation:

Substitute x = g(x) into f(x) , that is

f(g(x))

= f(2x - 3)

= (2x - 3)² ← expand using FOIL

= 4x² - 12x + 9

4 0
3 years ago
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