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Vladimir79 [104]

3 years ago

7

Enter the slope-intercept equation of the line that has slope 12 and yintercept (0, 3).

2 answers:

velikii [3]3 years ago

8 0

Answer:

y = 12x + 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = 12 and c = 3 , then

y = 12x + 3

Alekssandra [29.7K]3 years ago

5 0

Answer:

y= 12x+3

Step-by-step explanation:

The slope-intercept equation is basically y=mx+b

m is the slope and b is the intercept.

Plug the numbers in for those 2 and there's your answer :)

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Rewrite the expression in the form z^n

olga55 [171]

Answer:

${z}^{ \frac{1}{2} }$

Step-by-step explanation:

$\huge \sqrt[5]{ {z}^{4} {z}^{ - \frac{3}{2} } } \\ \\ = \huge \sqrt[5]{ {z}^{4 - \frac{3}{2} } } \\ \\ = \huge \sqrt[5]{ {z}^{ \frac{8 - 3}{2} } } \\ \\ = \huge \sqrt[5]{ {z}^{ \frac{5}{2} } } \\ \\ = \huge {z}^{ \frac{5}{2} \times \frac{1}{5} } \\ \\ = \huge {z}^{ \frac{1}{2} }$

3 0

3 years ago

A manufacturing company with 450 employees begins a new product line and must increase their number of employees by 18% how many

Artemon [7]

The company will have a total number of 531 employees

5 0

2 years ago

Whats the domain and range

Lerok [7]

Answer:

d= all the x values

r=all the y values

Step-by-step explanation:

7 0

2 years ago

The mean of the data set is 15.What number is missing? 9,12,16,18,23

maxonik [38]

The number 12 is missing in the data set.

<u>Step-by-step explanation</u>:

The numbers are 9,12,16,18,23.
The missing number is assumed to be 'x'

Mean = Sum of the integers / Total number of integers.

15 = (9+12+16+18+23+x) / 6

15 = (78+x) / 6

90 = 78+x

x = 90-78

x = 12

3 0

3 years ago

Find the smallest positive $n$ such that \begin{align*} n &\equiv 3 \pmod{4}, \\ n &\equiv 2 \pmod{5}, \\ n &\equiv

Alex777 [14]

4, 5, and 7 are mutually coprime, so you can use the Chinese remainder theorem right away.

We construct a number $x$ such that taking it mod 4, 5, and 7 leaves the desired remainders:

$x=3\cdot5\cdot7+4\cdot2\cdot7+4\cdot5\cdot6$

Taken mod 4, the last two terms vanish and we have

$x\equiv3\cdot5\cdot7\equiv105\equiv1\pmod4$

so we multiply the first term by 3.

Taken mod 5, the first and last terms vanish and we have

$x\equiv4\cdot2\cdot7\equiv51\equiv1\pmod5$

so we multiply the second term by 2.

Taken mod 7, the first two terms vanish and we have

$x\equiv4\cdot5\cdot6\equiv120\equiv1\pmod7$

so we multiply the last term by 7.

Now,

$x=3^2\cdot5\cdot7+4\cdot2^2\cdot7+4\cdot5\cdot6^2=1147$

By the CRT, the system of congruences has a general solution

$n\equiv1147\pmod{4\cdot5\cdot7}\implies\boxed{n\equiv27\pmod{140}}$

or all integers $27+140k$ , $k\in\mathbb Z$ , the least (and positive) of which is 27.

3 0

3 years ago